无法获得正确的温度转换输出

Question

好的，这样我的程序可以编译并很好地运行，但是目的是在摄氏，fahernheit和开尔文之间转换，并且当程序与客户端一起运行时，它显示正确的单位（F，C，K），但给出的值为在所有温度下均为50。 我该如何解决？

public class Temperature
{
private double value;
private String scale;

public Temperature()  // default constructor
{
  this.value = 0;
  this.scale = "C";
}

public Temperature(double value, String scale)
{
 this.value = value;
 this.scale = scale;     
}

public double getValue()
{
 return this.value;
}

 public String getScale()
 {
 return this.scale;
 }

 public double getCelsius()
 {

 if (scale.equalsIgnoreCase ("C"))
 {
     return this.value;
 }
 else if (scale.equalsIgnoreCase("F"))
 {
     double faren = ((this.value - 32) * (5/9));
     return faren;
 }
 else
 {
     double kelvin = (this.value - 273.15);
     return kelvin;
 }
 } // end getCelcius

 public double getFaren()
 {
 if (scale.equalsIgnoreCase ("F"))
 {
     return this.value;
 }
 else if (scale.equalsIgnoreCase("C"))
 {
     double celsius = ((this.value * 1.8) + 32);
     return celsius;
 }
 else
 {
     double kelvin = ((this.value * 1.8) - 459.67);
     return kelvin;
 }
 } // ene getFaren

 public double getKelvin()
 {
 if (scale.equalsIgnoreCase("K"))
 {
     return this.value;
 }
 else if (scale.equalsIgnoreCase("C"))
 {
     double celsius = (this.value + 273.15);
     return celsius;
 }
 else
 {
     double faren = ((this.value + 459.67) * (5/9));
     return faren;
 }
 } // end getKelvin

 public void setTemperature(Temperature t)
 {
 this.value = t.value;
 }

 public void setType(double degree, String measure)
 {
 this.value = degree;
 this.scale = measure;
 }

 public void setValue(double degree)
 {
 this.value = degree;
 }

 public void setScale(String measure)
 {
 this.scale = measure;
 }

 public double convertToCelsius()
 {
 this.scale = "C";
 return this.value = getCelsius();
 }

 public double convertToFaren()
 {
 this.scale = "F";
 return this.value = getFaren();
 }

 public double convertToKelvin()
 {
 this.scale = "K";
 return this.value = getKelvin();
 }

 public Temperature clone()
 {
 return new Temperature(this.value, this.scale);
 }

 public boolean equals()
 {
 return this.value == this.value && this.scale == this.scale; 
 }

 public String toString()
 {
 String temps = ("The temperature is " + this.value + "(" + this.scale + ")");
 return temps;
 }

 }

Answer 1

你应该改变

public double convertToKelvin() {
    this.scale = "K";
    return this.value = getKelvin();
}

至

public double convertToKelvin() {
    this.value = getKelvin()
    this.scale = "K";
    return value;
}

其他秤也一样。 首先要设置scale ，因此对象会看到scale是相同的，并且不进行转换。