在while循环中的PHP json_encode（）

Question

我正在尝试在while循环中使用json_encode()来获取数据库结果。 这是我的代码：

<?

$database = sqlite_open("thenew.db", 0999, $error);
if(!$database) die($error);

$query = "SELECT * FROM users";
$results = sqlite_query($database, $query);
if(!$results) die("Canot execute query");

while($row = sqlite_fetch_array($results)) {
  $data = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}
echo json_encode(array("response"=>$data));

sqlite_close($database);

?>

这个的输出是

{“响应”：“ lastUserID lastUser lastXPos lastYPos”}

我希望成为...

{“响应”：[“ 1亚历克斯10 12”，“ 2弗雷德27 59”，“ 3汤姆47 19”]}

等等

所以我想要json_encode()函数将所有用户放入数组，而不是最后一个。 我该怎么做？ 谢谢

Answer 1

尝试：

<?

$database = sqlite_open("thenew.db", 0999, $error);
if(!$database) die($error);

$query = "SELECT * FROM users";
$results = sqlite_query($database, $query);
if(!$results) die("Canot execute query");

$data = array();

while($row = sqlite_fetch_array($results)) {
  $data[] = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}
echo json_encode(array("response"=>$data));

sqlite_close($database);

?>

Answer 2

改变这个

while($row = sqlite_fetch_array($results)) {
  $data = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}

至

$data = array();
while($row = sqlite_fetch_array($results)) {
  $data[] = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}

Answer 3

将每个用户推送到一个数组：

$data = array();
while($row = sqlite_fetch_array($results)) {
  $data[] = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}
echo json_encode(array("response"=>$data));