[英]calculate total login logout time in mysql
mysql> select * from timing;
+--------------+---------------------+-----------------+
| employeeIdNo | employeeLogTime | employeeLogType |
+--------------+---------------------+-----------------+
| 1 | 2011-08-16 14:59:08 | login |
| 1 | 2011-08-16 15:00:06 | logout |
| 1 | 2011-08-16 15:14:51 | login |
| 2 | 2011-08-16 15:15:00 | login |
| 1 | 2011-08-16 15:59:01 | logout |
| 2 | 2011-08-16 15:59:09 | logout |
+--------------+---------------------+-----------------+
我想使用上述数据显示员工的总工作时间。 所以我想要一个 mysql 查询来计算(比如说)employeeIdNo=1 的总时间。 我的表名是时间,employeeIdNo 是表employee 的外键引用。 计算后它应该返回给我 totalLogTime 值 = 00:45:52(这是大约值,我没有准确计算)。 请向我提供适当的查询。 提前致谢。
我试过这个查询。:-
mysql> SELECT
TIMEDIFF(FIRSTTIME.employeeLogTime,SECONDTIME.employeeLogTime)
FROM (
(SELECT * FROM timing HAVING employeeLogTime = max(employeeLogTime)) as FIRSTTIME,
(SELECT * FROM timing ORDER BY employeeLogTime LIMIT 1,1) as SECONDTIME);
Empty set (0.01 sec)
它给了我空集,如上图所示。
你不能为单个用户总结所有时间:
并返回 B - A;
作为一种查看方式,这有点不合时宜,但提供了更简单的 sql 查询。 您还需要使用此方法检查登录和注销的出现次数是否相同。
检查显示
SELECT employeeIdNo ,sec_to_time(SUM(TIME)) FROM
(
SELECT
TO_SECONDS(employeeLogTime ) * -1 AS TIME
FROM connection
WHERE employeeLogType = 1
UNION
SELECT
TO_SECONDS(employeeLogTime ) * 1 AS TIME
FROM connection
WHERE employeeLogType = 0
) t
;
select employeeIdNo,
sum(loginTimeInSec) as loginTimeInSec
from(
select
e1.employeeIdNo,
TIME_TO_SEC(TIMEDIFF(e2.employeeLogTime,e1.employeeLogTime)) as loginTimeInSec
from
timing e1 join timing e2
on e1.employeeIdNo = e2.employeeIdNo
and e1.employeeLogType = 'login'
and e2.employeeLogType = 'logout'
and e1.employeeLogTime < e2.employeeLogTime
group by e1.id having min(e2.employeeLogTime - e1.employeeLogTime)
) temp
group by employeeIdNo;
通过将login
更改为1
并将logout
更改为0
来修改employeeLogType
列。 该表将如下所示:
mysql> select * from timing;
+--------------+---------------------+-----------------+
| employeeIdNo | employeeLogTime | employeeLogType |
+--------------+---------------------+-----------------+
| 1 | 2011-08-16 14:59:08 | 1 |
| 1 | 2011-08-16 15:00:06 | 0 |
| 1 | 2011-08-16 15:14:51 | 1 |
| 2 | 2011-08-16 15:15:00 | 1 |
| 1 | 2011-08-16 15:59:01 | 0 |
| 2 | 2011-08-16 15:59:09 | 0 |
+--------------+---------------------+-----------------+
查询显示所有员工的总时间:
mysql> SELECT employeeIdNo, time(sum(employeeLogTime*(1-2*`employeeLogType`)))
FROM timing GROUP BY employeeIdNo;
查询显示特定员工的总时间:
mysql> SELECT employeeIdNo, time(sum(employeeLogTime*(1-2*`employeeLogType`)))
FROM timing where employeeIdNo=(employeeIdNo) GROUP BY employeeIdNo;
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