[英]Separate digits in an NSString to display a phone number
我有一个NSString
,它包含这样的东西:
4434332124
我怎么能把它变成这样的东西?
443-433-2124
这只能在两行中完成,只需使用NSString的stringWithFormat方法,并将电话号码分成单独的子串,并将整个事物粘贴在您的格式字符串中。 像这样的东西:
NSString *sPhone = @"4434332124";
NSString *formatted = [NSString stringWithFormat: @"%@-%@-%@", [sPhone substringWithRange:NSMakeRange(A,B)],[sPhone substringWithRange:NSMakeRange(B,C)],
[sPhone substringWithRange:NSMakeRange(C,D)]];
编辑:工作代码
NSString *formatted = [NSString stringWithFormat: @"%@-%@-%@", [sPhone substringWithRange:NSMakeRange(0,3)],[sPhone substringWithRange:NSMakeRange(3,3)],
[sPhone substringWithRange:NSMakeRange(6,4)]];
如果你想简单快速地替换你确定的10位数字,那么试试这个正则表达式的例子( iOS> = 3.2 )。
NSString *tenDigitNumber = @"5554449999";
tenDigitNumber = [tenDigitNumber stringByReplacingOccurrencesOfString:@"(\\d{3})(\\d{3})(\\d{4})"
withString:@"$1-$2-$3"
options:NSRegularExpressionSearch
range:NSMakeRange(0, [tenDigitNumber length])];
NSLog(@"%@", tenDigitNumber);
不像尝试使用NSFormatter做一些漂亮的东西(虽然除非你将它子类化,否则我没有看到明显的方法让它做类似电话号码的事情)但你可以这样做:
NSString* newString = [NSString stringWithFormat:@"%c%c%c-%c%c%c-%c%c%c%c" [phoneNumber characterAtIndex:0],
[phoneNumber characterAtIndex:1],
[phoneNumber characterAtIndex:2],
[phoneNumber characterAtIndex:3],
[phoneNumber characterAtIndex:4],
[phoneNumber characterAtIndex:5],
[phoneNumber characterAtIndex:6],
[phoneNumber characterAtIndex:7],
[phoneNumber characterAtIndex:8],
[phoneNumber characterAtIndex:9]];
#import <Foundation/Foundation.h>
static NSString * const theInString = @"4434332124";
int main (int argc, const char * argv[])
{
NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init];
const char * theUniChar = theInString.UTF8String;
NSMurableString * theResult = nil;
for( int i = 0, c = (int)strlen(theUniChar); i < c; i+=2 )
{
char thePart[4];
sscanf( theUniChar + i, "%3s", &thePart );
if( theResult == nil )
theResult = [NSMutableString string];
else
[theResult appendFormate:@"-%3s",thePart];
}
printf( "%@\n", theResult );
[pool drain];
return 0;
}
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