MySQL查询问题-连接和分组

Question

我以一种更简单的方式重新发布了这个问题，因为我收到有关它过于具体的评论：

根据以下旅行模型之间的关系，如何选择在X 区域中具有至少一个停靠点的所有行程 ，并且仍然让查询返回该行程的所有停靠点 ，即使其他停靠点不在 X以外的区域中

我正在使用Php，MySQL和Doctrine。

Region HAS MANY Country
Country HAS MANY Area
Area HAS MANY Property
Property HAS MANY Stop 
Itinerary HAS MANY Stop

Answer 1

SELECT i.*
     , sa.*
FROM Itinerary AS i
  JOIN Stop AS sa
    ON i.ItineraryId = sa.ItineraryId
WHERE EXISTS
      ( SELECT *
        FROM Stop AS s
          JOIN Property AS p
            ON p.PropertyId = s.PropertyId
          JOIN Area AS a
            ON a.AreaId = p.AreaId
          JOIN Country AS c
            ON c.CountryId = a.CountryId 
          JOIN Region AS r
            ON r.RegionId  = c.RegionId
        WHERE s.ItineraryId = i.ItineraryId
          AND r.Name = @X
      ) 

Answer 2

从EXISTS所在的路线中选择*（从stop = X的路线中选择*）；

Answer 3

SELECT * from Itinerary where id in(
SELECT DISTINCT Itinerary.id
FROM Itinerary
LEFT JOIN Stop on Itinerary.something = Stop.something
LEFT JOIN Property ON Stop.something=Property.something
LEFT JOIN Area ON Area.something=Property.something
LEFT JOIN Country ON Country.something=Area.something
LEFT JOIN Region ON Region.something = Country.something
WHERE Region.something = X)