Rails模型继承和路由

Question

class User < ActiveRecord::Base
  has_many :queued_workouts, 
           :conditions => "queue_position IS NOT NULL",
           :order => "queue_position ASC"

  has_many :workouts
end

class Workout < ActiveRecord::Base
end

class QueuedWorkout < Workout
  # Have to give this its own class because acts_as_list always updates the
  # queue_position when operating on user.workouts
  acts_as_list :column => :queue_position, :scope => :user
end

我有用于锻炼的路线，但对于QueuedWorkout则不需要它们。 偶尔我遇到一种情况，我将QueuedWorkout而不是Workout传递给url_for。 在我的特定情况下，这是在WorkoutObserver中发生的。

现在我在做

class WorkoutObserver < ActiveRecord::Observer
  def after_update(workout)
    workout = Workout.find(workout.id) if workout.is_a? QueuedWorkout
    twitter_status = "some stuff " + short_url_for(workout)  # Helper method for generating urls outside controllers & views
    ....
  end
end

当然，这是一个糟糕的解决方案。 有没有更好的方法告诉Rails路由器为QueuedWorkouts生成锻炼URL？

Answer 1

你可以做：

resources :queued_workout, :controller => "workout"