从AsyncTask类返回数据

Question

如何从AsyncTask获取数据？ 我的MainActivity正在调用触发AsyncTask的DataCall.getJSON函数，但我不确定如何将数据恢复到原始Activity。

调用DataCall的MainActivity应该返回一个字符串并将其保存在state_data

String state_data =  DataCall.getJSON(spinnerURL,spinnerContentType); 

DataCall：

public class DataCall extends Activity {
    private static final String TAG = "MyApp";


    private class DownloadWebPageTask extends AsyncTask<String, Void, String> {


        protected String doInBackground(String... urls) {
            String response = "";
            for (String url : urls) {
                DefaultHttpClient client = new DefaultHttpClient();
                HttpGet httpGet = new HttpGet(url);
                try {
                    HttpResponse execute = client.execute(httpGet);
                    InputStream content = execute.getEntity().getContent();

                    BufferedReader buffer = new BufferedReader(
                            new InputStreamReader(content));
                    String s = "";
                    while ((s = buffer.readLine()) != null) {
                        response += s;
                    }

                } catch (Exception e) {
                    e.printStackTrace();
                }
            }
            return response;
        }


        protected void onPostExecute(String result) {
            //THIS IS WHERE I NEED TO RETURN MY DATA TO THE MAIN ACTIVITY. (I am guessing)
        }

        }

    public void getJSON(String myUrlString, String contentType) {
        DownloadWebPageTask task = new DownloadWebPageTask();
        task.execute(new String[] { "http://www.mywebsite.com/" + myUrlString });

    }

}

Answer 1

修改你的AsyncTask如下：

public class GetData extends AsyncTask<String, Void, String>
{
    DataDownloadListener dataDownloadListener;
    public GetData()
    {
        //Constructor may be parametric 
    }
    public void setDataDownloadListener(DataDownloadListener dataDownloadListener) {
        this.dataDownloadListener = dataDownloadListener;
    }
    @Override
    protected Object doInBackground(Object... param) 
    {
        // do your task...
        return null;
    }
    @Override
    protected void onPostExecute(Object results)
    {       
        if(results != null)
        {               
        dataDownloadListener.dataDownloadedSuccessfully(results);
        }
        else
        dataDownloadListener.dataDownloadFailed();
    }
    public static interface DataDownloadListener {
        void dataDownloadedSuccessfully(Object data);
        void dataDownloadFailed();
    }
}

并在您的活动中使用它

GetData getdata = new GetData();
getdata.setDataDownloadListener(new DataDownloadListener()
{
    @SuppressWarnings("unchecked")
    @Override
    public void dataDownloadedSuccessfully(Object data) {
    // handler result
    }
    @Override
    public void dataDownloadFailed() {
    // handler failure (e.g network not available etc.)
    }
});
getdata.execute("");

---

注意 ：对于正在阅读此内容的人。

请考虑这篇文章，以获得最佳和可能正确的实施。

Answer 2

对我来说关键是创建一个名为URLWithParams的类，因为AsyncTask只允许1个类型的IN发送，我需要HTTP请求的URL和参数。

public class URLWithParams {

    public String url;
    public List<NameValuePair> nameValuePairs;

    public URLWithParams()
    {
        nameValuePairs = new ArrayList<NameValuePair>();
    }
}

然后我将它发送给JSONClient：

public class JSONClient extends AsyncTask<URLWithParams, Void, String> {
    private final static String TAG = "JSONClient";

    ProgressDialog progressDialog ;
    GetJSONListener getJSONListener;
    public JSONClient(GetJSONListener listener){
        this.getJSONListener = listener;
    }

    @Override
    protected String doInBackground(URLWithParams... urls) {
        return connect(urls[0].url, urls[0].nameValuePairs);
    }

    public static String connect(String url, List<NameValuePair> pairs)
    {
        HttpClient httpclient = new DefaultHttpClient();

        if(url == null)
        {
            Log.d(TAG, "want to connect, but url is null");
        }
        else
        {
            Log.d(TAG, "starting connect with url " + url);
        }

        if(pairs == null)
        {
            Log.d(TAG, "want to connect, though pairs is null");
        }
        else
        {
            Log.d(TAG, "starting connect with this many pairs: " + pairs.size());
            for(NameValuePair dog : pairs)
            {
                Log.d(TAG, "example: " + dog.toString());
            }
        }

        // Execute the request
        HttpResponse response;
        try {
            // Prepare a request object
            HttpPost httpPost = new HttpPost(url); 
            httpPost.setEntity(new UrlEncodedFormEntity(pairs));
            response = httpclient.execute(httpPost);
            // Examine the response status
            Log.i(TAG,response.getStatusLine().toString());

            BufferedReader reader = new BufferedReader(new InputStreamReader(response.getEntity().getContent(), "UTF-8"));
            String json = reader.readLine();
            return json;

        } catch (ClientProtocolException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        } catch (IOException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        return null;
    }



    @Override
    protected void onPostExecute(String json ) {
        getJSONListener.onRemoteCallComplete(json);
    }


    public interface GetJSONListener {
        public void onRemoteCallComplete(String jsonFromNet);
    }

}

然后像我这样从我的主类中调用它

public class BookCatalog implements GetJSONListener {
    private final String TAG = this.getClass().getSimpleName();

    private String catalog_url = "URL";

    private void getCatalogFromServer() {

        URLWithParams mURLWithParams = new URLWithParams();
        mURLWithParams.url = catalog_url;

        try {
            JSONClient asyncPoster = new JSONClient(this);
            asyncPoster.execute(mURLWithParams);
        } catch (Exception e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    }

    @Override
    public void onRemoteCallComplete(String jsonBookCatalogList) {

        Log.d(TAG, "received json catalog:");
        Log.d(TAG, jsonBookCatalogList);
    JSONObject bookCatalogResult;
    try {
        bookCatalogResult = (JSONObject) new JSONTokener(jsonBookCatalogList).nextValue();
        JSONArray books = bookCatalogResult.getJSONArray("books");

        if(books != null) {
            ArrayList<String> newBookOrdering = new ArrayList<String>();
            int num_books = books.length();
            BookCatalogEntry temp;

            DebugLog.d(TAG, "apparently we found " + Integer.toString(num_books) + " books.");
            for(int book_id = 0; book_id < num_books; book_id++) {
                JSONObject book = books.getJSONObject(book_id);
                String title = book.getString("title");
                int version = book.getInt("price");
            }
        }

    } catch (JSONException e) {
        e.printStackTrace();
    } 

    }


}

Answer 3

序列化然后读取它。 我知道的唯一方法。

Answer 4

虽然我不同意为这个简单的任务创建一个新的活动

startActivityForResult()

从另一个活动获取数据。

检查一下 。 您可以将数据存储到Intent的附加内容中。 但是，如果您有大量数据，最好将其写入文件，从另一个完成下载的活动中获取结果，然后读取该文件。

Answer 5

一些选择：

a）使你的bean实现Serializable接口，然后你可以通过Intent传递你的bean。

b）实现Application接口（需要在manifest中创建一个条目），在Application类中使用setter \\ getter方法。 您可以在AsyncTask中的Application中设置bean，然后从Activity中检索。

Answer 6

很抱歉这么晚回答，我想到这个时候你可能已经解决了这个问题。 当我在寻找别的东西时，我遇到了你的问题。 我在这里粘贴一个链接，可能对其他人有所帮助。