[英]SQL if statement with two tables
给出下表:
表对象
id Name rating
1 Megan 9
2 Irina 10
3 Vanessa 7
4 Samantha 9
5 Roxanne 1
6 Sonia 8
交换表
id swap_proposalid counterpartyid
1 4 2
2 3 2
每个人都想要十。 我想为伊琳娜(Irina)列出可能的掉期清单,其中ID 4和3不会出现,因为这些提议已经存在。
输出1
id Name rating
1 Megan 9
5 Roxanne 1
6 Sonia 8
谢谢
这应该可以解决问题:
SELECT o.id, o.Name, o.rating
FROM objects o
LEFT JOIN swap s on o.id = s.swap_proposalid
WHERE s.id IS NULL
AND o.Name != 'Irina'
这有效
SELECT mt2.ID, mt2.Name, mt2.Rating
FROM [MyTable] mt2 -- Other Candidates
, [MyTable] mt1 -- Candidate / Subject (Irina)
WHERE mt2.ID NOT IN
(
SELECT st.swap_proposalid
FROM SwapTable st
WHERE
st.counterpartyid = mt1.ID
)
AND mt1.ID <> mt2.ID -- Don't match Irina with Irina
AND mt1.Name = 'Irina' -- Find other swaps for Irina
- 测试数据
CREATE TABLE MyTable
(
ID INT,
Name VARCHAR(100),
Rating INT
)
GO
CREATE TABLE SwapTable
(
ID INT,
swap_proposalid INT,
counterpartyid INT
)
GO
INSERT INTO MyTable VALUES(1 ,'Megan', 9)
INSERT INTO MyTable VALUES(2 ,'Irina', 10)
INSERT INTO MyTable VALUES(3 ,'Vanessa', 7)
INSERT INTO MyTable VALUES(4 ,'Samantha', 9)
INSERT INTO MyTable VALUES(5 ,'Roxanne', 1)
INSERT INTO MyTable VALUES(6 ,'Sonia', 8)
INSERT INTO SwapTable(ID, swap_proposalid, counterpartyid)
VALUES (1, 4, 2)
INSERT INTO SwapTable(ID, swap_proposalid, counterpartyid)
VALUES (1, 3, 2)
猜测该逻辑涉及识别除最高评级对象外的对象以及最高评级对象,例如(使用示例DDL和@nonnb友善发布的数据):
WITH ObjectHighestRated
AS
(
SELECT ID
FROM MyTable
WHERE Rating = (
SELECT MAX(T.Rating)
FROM MyTable T
)
),
PropositionsForHighestRated
AS
(
SELECT swap_proposalid AS ID
FROM SwapTable
WHERE counterpartyid IN (SELECT ID FROM ObjectHighestRated)
),
CandidateSwappersForHighestRated
AS
(
SELECT ID
FROM MyTable
EXCEPT
SELECT ID
FROM ObjectHighestRated
EXCEPT
SELECT ID
FROM PropositionsForHighestRated
)
SELECT *
FROM MyTable
WHERE ID IN (SELECT ID FROM CandidateSwappersForHighestRated);
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