将数据表导出到现有的Excel

Question

我需要打开一个现有的Excel文件，并用DataTable填充它。 我怎样才能做到这一点？

我在ASP.NET中工作

我已经尝试使用此解决方案创建一个excel（http://stackoverflow.com/questions/1746701/export-datatable-to-excel-file），然后尝试使用此类OLEDB连接打开它，但是它没用..它说表的格式不正确..然后说ir找不到ISAM文件..我不知道该怎么办..

System.Data.OleDb.OleDbConnection conn = new System.Data.OleDb.OleDbConnection(@"Provider=Microsoft.Jet.OLEDB.4.0;DataSource=C:\reports\report.xls;Extended Properties=""Excel 8.0;HDR=No;IMEX=1""");

conn.Open();
System.Data.OleDb.OleDbCommand cmd = new System.Data.OleDb.OleDbCommand();
cmd.Connection = conn;

cmd.CommandText = @"SELECT * INTO [Excel 8.0;Database=C:\reports\reportBase.xls].[SheetBase1] FROM Sheet1]";

cmd.ExecuteNonQuery();
conn.Close();

请帮我！！ 我很绝望！！

谢谢！！

Answer 1

如果您也对第三方Excel .NET库感兴趣，则可以打开现有的Excel文件，并使用带有GemBox.Spreadsheet Excel C＃/ VB.NET库的数据表填充该文件。

这是一个Excel ASP.NET示例，如何打开现有的Excel文件，用DataTable填充并将其流式传输到浏览器：

DataTable people = (DataTable)Session["people"];

// Open excel file and insert data table.
ExcelFile ef = new ExcelFile();
ef.LoadXls(Server.MapPath("MyData.xls"));
ExcelWorksheet ws = ef.Worksheets[0];
ws.InsertDataTable(people, "A1", true);

Response.Clear();

// Stream file to browser, in required type.
switch (this.RadioButtonList1.SelectedValue)
{
    case "XLS":
        Response.ContentType = "application/vnd.ms-excel";
        Response.AddHeader("Content-Disposition", "attachment; filename=" +
             "Report.xls");
        ef.SaveXls(Response.OutputStream);
        break;

    case "XLSX":
        Response.ContentType = "application/vnd.openxmlformats";
        Response.AddHeader("Content-Disposition", "attachment; filename=" +
             "Report.xlsx");
        // With XLSX it is a bit more complicated as MS Packaging API
        // can't write directly to Response.OutputStream.
        // Therefore we use temporary MemoryStream.
        MemoryStream ms = new MemoryStream();
        ef.SaveXlsx(ms)
        ms.WriteTo(Response.OutputStream);
        break;
}
Response.End();

Answer 2

如果您也对第三方Excel .NET库感兴趣，则可以打开现有的Excel文件，并使用带有GemBox.Spreadsheet Excel C＃/ VB.NET库的数据表填充该文件。

另外，如果你不想花$ 480的许可，您可以下载我的导出到Excel C＃类完全免费的。

它使用OpenXML库创建真实的Excel 2007文件，只需指定文件名，然后调用“ CreateExcelDocument”函数。

DataSet ds = CreateSampleData();
string excelFilename = "C:\\Sample.xlsx";
CreateExcelFile.CreateExcelDocument(ds, excelFilename);

您可以从DataSet，DataTable或List <>创建Excel文件。

我的网页上完全免费提供了所有源代码，以及说明和演示项目：

http://mikesknowledgebase.com/pages/CSharp/ExportToExcel.htm

甚至还有一些示例代码，展示了如何在ASP.Net应用程序中创建Excel文件，然后将其打开。

祝好运 ！

Answer 3

您可以使用此解决方案...。仅在将数据放入数据表之后...。

 protected void Button1_Click(object sender, EventArgs e)
 {
     DataTable dtRecords = new DataTable();
     dtRecords.Columns.Add("FIRSTNAME");
     dtRecords.Columns.Add("LASTNAME");
     dtRecords.Columns.Add("JOB");
     DataRow rw1 = dtRecords.NewRow();
     rw1[0] = "JHON";
     rw1[1] = "SMITH";
     rw1[2] = "MANAGER";
     dtRecords.Rows.Add(rw1);
     DataRow rw2 = dtRecords.NewRow();
     rw2[0] = "MICH";
     rw2[1] = "KEN";
     rw2[2] = "SR MANAGER";
     dtRecords.Rows.Add(rw2);

     UploadDataTableToExcel(dtRecords);

}
protected void UploadDataTableToExcel(DataTable dtRecords)
{
        string XlsPath = Server.MapPath(@"~/Add_data/test.xls");
        string attachment = string.Empty;
        if (XlsPath.IndexOf("\\") != -1)
        {
            string[] strFileName = XlsPath.Split(new char[] { '\\' });
            attachment = "attachment; filename=" + strFileName[strFileName.Length - 1];
        }
        else
            attachment = "attachment; filename=" + XlsPath;
        try
        {
            Response.ClearContent();
            Response.AddHeader("content-disposition", attachment);
            Response.ContentType = "application/vnd.ms-excel";
            string tab = string.Empty;

            foreach (DataColumn datacol in dtRecords.Columns)
            {
                Response.Write(tab + datacol.ColumnName);
                tab = "\t";
            }
            Response.Write("\n");

            foreach (DataRow dr in dtRecords.Rows)
            {
                tab = "";
                for (int j = 0; j < dtRecords.Columns.Count; j++)
                {
                    Response.Write(tab + Convert.ToString(dr[j]));
                    tab = "\t";
                }

                Response.Write("\n");
            }
            Response.End();
        }
        catch (Exception ex)
        {
            //Response.Write(ex.Message);
        }
}

Answer 4

通过使用此belove代码，我得到了准确的结果.....

这可能对您有帮助。

 try
        {


            if (dt == null || dt.Columns.Count == 0)
            {
                throw new Exception("ExportToExcel: Null or empty input table!\n");
            }
            string Filepath = "E:Sample\\Form.xlsx";
            string SheetName = "Elnath - 3000";
           // Microsoft.Office.Interop.Excel.Application xlApp;
            Microsoft.Office.Interop.Excel.Workbook xlWorkBook;
            Microsoft.Office.Interop.Excel._Worksheet xlWorkSheet;
           // Microsoft.Office.Interop.Excel.Range xlRange = null;
           object misValue = Type.Missing;

            Excel.Application xlApp = new Excel.Application();
           xlWorkBook = xlApp.Workbooks.Add(Filepath);

           // xlWorkBook = xlApp.Workbooks.Open(Filepath, misValue, false, misValue, misValue, misValue, true, misValue, misValue, misValue, misValue, misValue, false, misValue, misValue);
            xlWorkSheet = (Microsoft.Office.Interop.Excel.Worksheet)xlWorkBook.Sheets[SheetName];

            xlWorkSheet = (Microsoft.Office.Interop.Excel.Worksheet)xlWorkBook.ActiveSheet;

            xlWorkSheet = (Microsoft.Office.Interop.Excel.Worksheet)xlWorkBook.Sheets.get_Item(SheetName);
            xlWorkSheet.Activate();
           // object StartRange = "B";
          //  object EndRange = misValue;

          //  xlRange = xlWorkSheet.get_Range("A", "M");
          //  xlRange = (Microsoft.Office.Interop.Excel.Range)xlWorkSheet.get_Range(StartRange, misValue);

            //Header
            //for (i = 0; i < dt.Columns.Count; i++)
            //{
            //    xlRange.Cells[1, i + 1] = dt.Columns[i].ColumnName;

            //}
            //Datas
            for (int i = 0; i < dt.Rows.Count; i++)
            {
                for (int j = 0; j < dt.Columns.Count; j++)
                {
                    xlApp.Cells[i + 13, j + 1] = dt.Rows[i][j].ToString();
                }
            }
            if (Filepath != null || Filepath != "")
            {
                try
                {
                    xlApp.ActiveWorkbook.SaveAs(Filepath);
                    xlApp.Quit();

                    xlWorkSheet = null;
                    xlWorkBook = null;
                    xlApp = null;
                }
                catch (Exception ex)
                {
                    throw new Exception("Can not save file" + ex.Message);
                }
            }
            else
            {
                xlApp.Visible = true;
            }
            return dt;
        }
        catch (Exception ex)
        {
            throw new Exception(ex.Message);
        }