在MySQL慢查询日志中优化查询

Question

设置数据库是为了使我们拥有一个credentials表，其中包含多种不同类型的凭证（登录等）。 还有一个credential_pairs表将这些类型中的某些类型关联在一起（例如，用户可能具有密码和安全令牌）。

为了查看对是否匹配，有以下查询：

SELECT DISTINCT cp.credential_id FROM credential_pairs AS cp
INNER JOIN credentials AS c1 ON (cp.primary_credential_id   = c1.credential_id)
INNER JOIN credentials AS c2 ON (cp.secondary_credential_id = c2.credential_id)
WHERE c1.data = AES_ENCRYPT('Some Value 1', 'encryption key')
AND   c2.data = AES_ENCRYPT('Some Value 2', 'encryption key');

该查询可以正常工作，并为我们提供所需的确切信息。 但是，它一直在缓慢的查询日志中显示（可能由于缺少索引？）。 当我要求MySQL“解释”查询时，它给了我：

+----+-------------+-------+------+--------------------------------------------------------+---------------------+---------+-------+-------+--------------------------------+
| id | select_type | table | type | possible_keys                                          | key                 | key_len | ref   | rows  | Extra                          |
+----+-------------+-------+------+--------------------------------------------------------+---------------------+---------+-------+-------+--------------------------------+
|  1 | SIMPLE      | c1    | ref  | credential_id_UNIQUE,credential_id,ix_credentials_data | ix_credentials_data | 22      | const |     1 | Using where; Using temporary   |
|  1 | SIMPLE      | c2    | ref  | credential_id_UNIQUE,credential_id,ix_credentials_data | ix_credentials_data | 22      | const |     1 | Using where                    |
|  1 | SIMPLE      | cp    | ALL  | NULL                                                   | NULL                | NULL    | NULL  | 69197 | Using where; Using join buffer |
+----+-------------+-------+------+--------------------------------------------------------+---------------------+---------+-------+-------+--------------------------------+

我觉得最后一个条目（显示69197行）可能是问题所在，但我是DBA的FAR ...帮助？

---

凭证表：

CREATE TABLE  `credentials` (
  `hidden_id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `credential_id` varchar(255) NOT NULL,
  `data` blob NOT NULL,
  `credential_status` varchar(100) NOT NULL,
  `insert_date` datetime NOT NULL,
  `insert_user` int(10) unsigned NOT NULL,
  `update_date` datetime DEFAULT NULL,
  `update_user` int(10) unsigned DEFAULT NULL,
  `delete_date` datetime DEFAULT NULL,
  `delete_user` int(10) unsigned DEFAULT NULL,
  `is_deleted` tinyint(1) NOT NULL DEFAULT '0',
  PRIMARY KEY (`hidden_id`,`credential_id`),
  UNIQUE KEY `credential_id_UNIQUE` (`credential_id`),
  KEY `credential_id` (`credential_id`),
  KEY `data` (`data`(10)),
  KEY `credential_status` (`credential_status`(10))
) ENGINE=InnoDB AUTO_INCREMENT=1572 DEFAULT CHARSET=utf8;

credential_pairs表：

CREATE TABLE  `credential_pairs` (
  `hidden_id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `credential_id` varchar(255) NOT NULL,
  `primary_credential_id` varchar(255) NOT NULL,
  `secondary_credential_id` varchar(255) NOT NULL,
  `is_deleted` tinyint(1) DEFAULT NULL,
  PRIMARY KEY (`hidden_id`,`credential_id`),
  KEY `primary_credential_id` (`primary_credential_id`(10)),
  KEY `secondary_credential_id` (`secondary_credential_id`(10))
) ENGINE=InnoDB AUTO_INCREMENT=500 DEFAULT CHARSET=latin1;

凭证索引：

+-------------+------------+----------------------+--------------+---------------+-----------+-------------+----------+--------+------+------------+---------+
| Table       | Non_unique | Key_name             | Seq_in_index | Column_name   | Collation | Cardinality | Sub_part | Packed | Null | Index_type     | Comment |
+-------------+------------+----------------------+--------------+---------------+-----------+-------------+----------+--------+------+------------+---------+
| credentials |          0 | PRIMARY              |            1 | hidden_id     | A         |      186235 |     NULL | NULL   |      | BTREE      |         |
| credentials |          0 | PRIMARY              |            2 | credential_id | A         |      186235 |     NULL | NULL   |      | BTREE      |         |
| credentials |          0 | credential_id_UNIQUE |            1 | credential_id | A         |      186235 |     NULL | NULL   |      | BTREE      |         |
| credentials |          1 | credential_id        |            1 | credential_id | A         |      186235 |     NULL | NULL   |      | BTREE      |         |
| credentials |          1 | ix_credentials_data  |            1 | data          | A         |      186235 |       20 | NULL   |      | BTREE      |         |
+-------------+------------+----------------------+--------------+---------------+-----------+-------------+----------+--------+------+------------+---------+

credential_pair索引：

+------------------+------------+---------------------------------------------+--------------+-------------------------+-----------+-------------+----------+--------+------+------------+---------+
| Table            | Non_unique | Key_name                                    | Seq_in_index | Column_name             | Collation | Cardinality | Sub_part | Packed | Null | Index_type | Comment |
+------------------+------------+---------------------------------------------+--------------+-------------------------+-----------+-------------+----------+--------+------+------------+---------+
| credential_pairs |          0 | PRIMARY                                     |            1 | hidden_id               | A         |       69224 |     NULL | NULL   |      | BTREE      |         |
| credential_pairs |          0 | PRIMARY                                     |            2 | credential_id           | A         |       69224 |     NULL | NULL   |      | BTREE      |         |
| credential_pairs |          1 | ix_credential_pairs_credential_id           |            1 | credential_id           | A         |       69224 |       36 | NULL   |      | BTREE      |         |
| credential_pairs |          1 | ix_credential_pairs_primary_credential_id   |            1 | primary_credential_id   | A         |       69224 |       36 | NULL   |      | BTREE      |         |
| credential_pairs |          1 | ix_credential_pairs_secondary_credential_id |            1 | secondary_credential_id | A         |       69224 |       36 | NULL   |      | BTREE      |         |
+------------------+------------+---------------------------------------------+--------------+-------------------------+-----------+-------------+----------+--------+------+------------+---------+

---

更新说明：

AFAICT：DISTINCT是多余的……真的不需要它，所以我删除了它。 为了遵循Fabrizio的建议，在credential_pairs查找中找到位置，然后将语句更改为：

SELECT credential_id 
FROM credential_pairs cp
WHERE cp.primary_credential_id = (SELECT credential_id FROM credentials WHERE data = AES_ENCRYPT('value 1','enc_key')) AND
    cp.secondary_credential_id = (SELECT credential_id FROM credentials WHERE data = AES_ENCRYPT('value 2','enc_key'))

没事了。 该语句花了很长时间，并且解释看起来几乎相同。 因此，我使用以下命令向主列和辅助列添加了索引：

ALTER TABLE credential_pairs ADD INDEX `idx_credential_pairs__primary_and_secondary`(`primary_credential_id`, `secondary_credential_id`);

没事了。

+----+-------------+-------------+-------+---------------------+---------------------------------------------+---------+------+-------+--------------------------+
| id | select_type | table       | type  | possible_keys       | key                                         | key_len | ref  | rows  | Extra                    |
+----+-------------+-------------+-------+---------------------+---------------------------------------------+---------+------+-------+--------------------------+
|  1 | PRIMARY     | cp          | index | NULL                | idx_credential_pairs__primary_and_secondary | 514     | NULL | 69217 | Using where; Using index |
|  3 | SUBQUERY    | credentials | ref   | ix_credentials_data | ix_credentials_data                         | 22      |      |     1 | Using where              |
|  2 | SUBQUERY    | credentials | ref   | ix_credentials_data | ix_credentials_data                         | 22      |      |     1 | Using where              |
+----+-------------+-------------+-------+---------------------+---------------------------------------------+---------+------+-------+--------------------------+

它说它正在使用索引，但看起来仍然像是表扫描。 因此，我添加了一个联合键（按照下面的评论）：

ALTER TABLE credential_pairs ADD KEY (primary_credential_id, secondary_credential_id);

并且...与索引的结果相同（这些功能是否相同？）。

Answer 1

DISTINCT是生成“使用临时”的原因，您通常希望尽可能避免使用

另外，由于您没有针对它的任何条件，因此您正在扫描整个credential_pair表，因此不使用任何索引，并且在应用WHERE之前将返回整个表

希望有道理

编辑/添加

尝试从另一个表开始，如果我理解正确，那么您具有表A，表B和表AB，并且您正在从AB开始选择，请尝试从A开始

我尚未对此进行测试，但是您可以尝试：

SELECT cp.credential_id
FROM credentials AS c1
    LEFT JOIN credential_pairs AS cp ON (c1.credential_id = cp.primary_credential_id)
    LEFT JOIN credentials AS c2 ON (cp.secondary_credential_id = c2.credential_id)
WHERE
    c1.data = AES_ENCRYPT('Some Value 1', 'encryption key')
    AND c2.data = AES_ENCRYPT('Some Value 2', 'encryption key');

过去，我通过移动选择表来获得好运