[英]How to post both a javascript variable and a html form via $.ajax post?
[英]how to run javascript in html loaded via ajax
我有一个index.php文件,可通过此javascript / ajax代码加载其他php文件:
function AJAX(elementID,url,showStatus){
var httpObject;
if (window.ActiveXObject) {
httpObject = new ActiveXObject("Microsoft.XMLHTTP");
}
if (window.XMLHttpRequest){
httpObject = new XMLHttpRequest();
}
else {
alert("Your browser does not support AJAX.");
}
if (httpObject != null) {
httpObject.onreadystatechange = function() {
if (elementID != false){
if (httpObject.readyState == 4 && httpObject.status == 200) {
document.getElementById(elementID).innerHTML= httpObject.responseText;
}
}
}
httpObject.open("POST",url,true);
httpObject.send(null);
}
}
因此,例如,我将通过以下方式在inxex.php中加载文件:
<script>
AJAX("updateThisDiv", "/includes/contentpage.php", false)
</script>
这会将“ contentpage.php”的内容粘贴到div“ updateThisDiv”中,但是现在如果我在“ contentpage.php”上有任何JavaScript,它将无法运行,有什么办法吗?
我已经看过了: http : //www.javascriptkit.com/script/script2/ajaxpagefetcher.shtml,但这并不是我要找的东西。
我希望能够更新页面的一部分而无需重新加载整个页面,并且必须运行javascript
如果动态插入脚本标签,则代码将执行。 请勿使用评估。 图书馆知道这一点,他们也不使用eval(除非它们很糟糕)。
如果要按需加载Javascript。 这可以通过动态创建脚本标签来完成。 Stoyan Stefanov书-Javascript Patterns中说明了这种模式
这是从书中摘录的:
编写一个require函数。 然后这样称呼它:
require("extra.js", function () {
functionDefinedInExtraJS();
});
样品需求功能:
function require(file, callback) {
var script = document.getElementsByTagName('script')[0],
newjs = document.createElement('script');
// IE
newjs.onreadystatechange = function () {
if (newjs.readyState === 'loaded' || newjs.readyState === 'complete') {
callback();
}
};
// others
newjs.onload = function () {
callback();
};
newjs.src = file;
script.parentNode.insertBefore(newjs, script);
}
在http://www.jspatterns.com/book/8/ondemand.html中找到的实时示例
@Edit:针对您的情况的更多详细信息。 我将尝试使事情变得简单:
创建fours文件:
的index.php
<html>
<head>
<script src="code.js"></script>
</head>
<body>
<input type="button" onclick="Ajax('content.php', 'd_html');" value="Fill from content.php"/>
<div id="d_html"></div>
<br>
<input type="button" onclick="Ajax('content.js', 'd_js');" value="Fill from content.js"/>
<div id="d_js"></div>
</body>
</html>
content.php
<span>Hello, I am dynamic span came from content.php</span>
content.js
//Ana javascript code you want to run it by Ajax function should go inside this function
function executeJS(element){
element.innerHTML = "<span>Hello, I am dynamic span came from content.js</span>";
}
code.js
//This function responsible for doing the ajax request for any file that will return pure HTML.
function getHTML(url, element){
var i, xhr, activeXids = [
'MSXML2.XMLHTTP.3.0',
'MSXML2.XMLHTTP',
'Microsoft.XMLHTTP'
];
if (typeof XMLHttpRequest === "function") { // native XHR
xhr = new XMLHttpRequest();
} else { // IE before 7
for (i = 0; i < activeXids.length; i += 1) {
try {
xhr = new ActiveXObject(activeXids[i]);
break;
} catch (e) {}
}
}
xhr.onreadystatechange = function () {
if (xhr.readyState !== 4) {
return false;
}
if (xhr.status !== 200) {
alert("Error, status code: " + xhr.status);
return false;
}
element.innerHTML += xhr.responseText;
};
xhr.open("GET", url, true);
xhr.send("");
}
//This function will load javascript file on-demand and call executeJS function inside that file.
function getJS(url, element, cb){
var newjs = document.createElement('script');
// IE
newjs.onreadystatechange = function () {
if (newjs.readyState === 'loaded' || newjs.readyState === 'complete') {
cb();
}
};
// others
newjs.onload = function () {
cb();
};
newjs.src = url;
element.appendChild(newjs);
}
//This is same as your function, but now can handle both PHP and JS files
function Ajax(url, id){
var element = document.getElementById(id),
regex = /\.js$/;
if(!element){
alert("Invalid ID");
return false;
}
if(regex.test(url)){ //If url ends with JS, load using getJS
getJS(url, element, function(){
executeJS(element);
});
} else {
getHTML(url, element);
}
}
这有效100%.....但我宁愿不使用jquery
<!DOCTYPE html>
<html dir=”ltr” lang=”en-US”>
<head>
<meta charset=”UTF-8” />
<title>AJAX Detection And Data Loading Using New School jQuery & HTML5:</title>
<script src=”https://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.js”
type=”text/javascript”></script>
<script type="text/javascript">
$(document).ready(function(){
$("button").click(function () {
$("#mm").load("test.php");
});
});
</script>
</head>
<body>
<button type=”button”>Load Some Copy!</button>
<div id="mm">
</div>
<section>
</section>
</body>
</html>
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