[英]Foreach loop + associative array
如果我有以下代码:
$employeeAges;
$employeeAges["Lisa"] = "28";
$employeeAges["Jack"] = "16";
$employeeAges["Ryan"] = "35";
$employeeAges["Rachel"] = "46";
$employeeAges["Grace"] = "34";
foreach( $employeeAges as $name => $age){
echo "Name: $name, Age: $age <br />";
}
如何输出特定信息? 下面是一个错误编写的示例:
foreach( $employeeAges as $name => $age ) {
$selective = $name["Lisa"]->$age;
$secondary = $name["Grace"]->$age;
echo "The person you're looking for is $selective years old. And the other one is $secondary years old.";
}
如您所见,我只想获取特定项$ key的$ value。 上面的代码输出以下错误:
Trying to get property of non-object
有人可以帮忙这段代码吗? 不胜感激。
如果我了解您没错,而您只是想知道某个人的年龄,请执行以下操作:
$selective = $employeeAges["Lisa"];
$secondary = $employeeAges["Grace"];
echo "The person you're looking for is $selective years old. And the other one is $secondary years old.";
->
运算符用于访问对象的命名成员。 参见: http : //www.php.net/manual/en/language.oop5.basic.php
如注释中所述,要遍历数组以查找特定键,请执行以下操作:
foreach ($employeeAges as $name => $age) {
if ($name == "Grace") {
echo $name . " is " . $age . " years old";
break;
}
}
我对问题的理解不同
<?php
//Assuming this is your array
$employeeAges["Lisa"] = "28";
$employeeAges["Jack"] = "16";
$employeeAges["Ryan"] = "35";
$employeeAges["Rachel"] = "46";
$employeeAges["Grace"] = "34";
echo $employeeAges["Lisa"]; //Will output 28
echo $employeeAges["Jack"]; //Will output 16
echo $employeeAges["Grace"]; //Will output 34
您只需要指定所需的键,它将输出值。
因此,您只想打印出年龄吗?
$employeeAges;
$employeeAges["Lisa"] = "28";
$employeeAges["Jack"] = "16";
$employeeAges["Ryan"] = "35";
$employeeAges["Rachel"] = "46";
$ employeeAges [“ Grace”] =“ 34”;
foreach($employeeAges as $name=>$age) {
echo $age;
}
使用这样的foreach循环,只需将键强制为$name
,将值强制为$age
而不必调用对象,因此会出现错误。
我认为@jli有一个更好的答案适合您的问题。
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