根据父数组对字符串数组进行排序？

Question

我有几个月的正确顺序：

    String[] monthOrder = {"January","Febuary","March","April","May","June","July","August","September","October","November","December"};

而且我有几个月的时间顺序不正确。 。 。

我该如何按不正确的顺序对月份数组进行排序，使其类似于正确的顺序。

编辑：

让我澄清一下，我正在从SQL Server读取表，它们最终将变成乱序，我可能甚至没有全部12个月的时间。 然后，我使用JFreeGraph从读取的表中绘制一个数字。X轴标签必须是我按正确顺序排列的月份数。 抱歉，一开始没有校准...

编辑2：代码：

  DefaultCategoryDataset dataset = new DefaultCategoryDataset();
        m.setDatabase("Sioux Falls, SD");

int i = 0;
String newMonth = "";
String[] monthOrder = {"January","Febuary","March","April","May","June","July","August","September","October","November","December"};

   Set<String> sqlMonths = new HashSet<String>();
while(i < m.getAmountOfDateTables()){

    String date = m.getDateTables(i); //Gets the name of the table off the sql server FORMAT: Month Year
    int index = date.indexOf(" "); //gets the index of the space to separate the month and year
    String year = date.substring(index+1); //gets the year
    int currentYearInt = Calendar.getInstance().get(Calendar.YEAR); //gets current year
    String currentYear = String.valueOf(currentYearInt);//converts to string
    System.out.println(year);//test

    //I have a table called current need to ignore it.
    if(date.equalsIgnoreCase("current")){

    }else{

 newMonth = date.substring(0,index); //gets the month
    }



    if(year.equalsIgnoreCase(currentYear) || year.equalsIgnoreCase("current")){ //making sure it doesnt graph anything from past or future years...

    //dataset.addValue(m.getTotalForPersonInMonth(SalesPerson,m.getDateTables(i), Store),"Sales" , m.getDateTables(i)); THIS IS FOR GRAPHING WILL CHANGE WHEN SORTING IS DONE
        if(date.equalsIgnoreCase("Current")){

        }else{
            sqlMonths.add(newMonth); //add to sql months...
        }
        i++;

        //USED WHILE BECUASE FOR LOOP WOULDNT RUN WHILE WAS EASIER ANYWAY.

}else{

}

}

List<String> sortedMonths = new ArrayList<String>(); //your code
System.out.println(sqlMonths +" From sever"); //printing out sqlMonths
for (String month : monthOrder) {
  if (sqlMonths.contains(month))
    sortedMonths.add(month);
}
   System.out.println(sortedMonths +" Sorted");

        return dataset;



    }

对不起，混乱：S

编辑3：哦，我我觉得很愚蠢……案子已经关闭了！ :)非常感谢havexz！

Answer 1

这是您可以做的...

从SQL Server获得的作为HashSet创建。 然后有这个逻辑。

String[] monthOrder = { "January", "Febuary", "March", "April", "May", "June", "July",
                "August", "September", "October", "November", "December" };
Set<String> sqlMonths = new HashSet<String>();
// Write your code to load the sqlMonths.
sqlMonths.add("March");
sqlMonths.add("December");
sqlMonths.add("Febuary");
List<String> sortedMonths = new ArrayList<String>();

for (String month : monthOrder) {
  if (sqlMonths.contains(month))
    sortedMonths.add(month);
}
System.out.println(sortedMonths);

OUTPUT：

[Febuary, March, December]

希望这能解决您的问题。

注意：即使是这种情况，months的值也应与monthOrder完全匹配。

Answer 2

一种方法是创建一个Map，在其中每个字符串都与其索引相对应： {"January" : 0, "February : 1, ...} 。然后编写一个Comparator，它接受两个字符串，并同时查找它们在地图中进行比较，然后比较生成的int。如何处理未出现在地图中的字符串是一个问题-如果您知道永远不会发生，则可能应该抛出异常，或者将所有排序列表的开头或结尾处的那些其他字符串（可能以确定性顺序，例如字母）。

Answer 3

在Java和其他语言中，您可以提供自己的比较器，例如在其中可以在正确的数组中查找字符串，并使用其索引位置作为数字值来确定顺序