![](/img/trans.png)
[英]ReferenceError: Can't find variable: ValidatorEnable in Safari
[英]safari ReferenceError: Can't find variable changestyledisplayblock
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.1//EN" "http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>The Goodies</title>
<link rel="stylesheet" href="core.css" type="text/css"/>
<meta name="generator" content="DocBook XSL Stylesheets V1.74.0"/>
<script type="text/javascript"> function changestyledisplayblock(id){ var ps = document.getElementsByTagName('p'); for (var i=0; i < ps.length; i++) { if (ps[i].id == id) { if ( ps[i].style.display == 'none' ) {ps[i].style.display = 'block';} else {ps[i].style.display = 'none';} } } } </script>
</head>
<body>
<div class="sect1" title="The Goodies">
<div class="sect2" title="Multimedia">
<div class="titlepage">
<div>
<div>
<h2 class="title">
<a id="multimedia">Multimedia</a>
</h2>
</div>
</div>
</div>
<p class="bubble speech" id="bubble-speech-0 " style="display:none;">*0 : My first one !</p>
<p class="bubble speech" id="bubble-speech-0 " style="display:none;">*0 : My second one !</p>
<p>text <a class="marker" href="javascript:changestyledisplayblock('bubble-speech-0 ')">*0 </a>next</p>
</div>
</div>
</body>
</html>
这是我的html,出现错误ReferenceError:找不到变量changestyledisplayblock,我没有看到任何错误,请帮忙! 如果我将html扩展名更改为xhtml,我再也看不到问题了??? 有什么解释吗?
“ <”应该是一个小于号。 还是在粘贴代码时出错?
另外,我建议不要在锚标记中调用javascript代码。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.