从AS3和PHP中的Flash网站将图像上传到服务器

Question

我一直在尝试创建此代码一段时间，只是想知道是否有人比我能读得更好的代码可能会弄清楚为什么图像无法最终显示在我的服务器上，因为我似乎对此不动了：(

var fileRef:FileReference = new FileReference(); 
fileRef.addEventListener(Event.SELECT, selectHandler); 
fileRef.addEventListener(Event.COMPLETE, completeHandler); 
try 
{ 
var success:Boolean = fileRef.browse(); 
} 
catch (error:Error) 
{ 
trace("Unable to browse for files."); 
} 
function selectHandler(event:Event):void 
{ 
var request:URLRequest = new URLRequest("http://localhost/upload.php") 
try 
{ 
fileRef.upload(request); 
} 
catch (error:Error) 
{ 
trace("Unable to upload file."); 
} 
} 
function completeHandler(event:Event):void 
{ 
trace("uploaded"); 
}
customerService.createClients(SlagsData);
}

然后这是服务器上的php

<?php
define('UPLOAD_DIR', 'c:/wamp/www/IMAGES/');
define('UPLOAD_DIR_default', 'c:/wamp/www/IMAGES/0/image01.jpg');
$hostname_thatexclients = "localhost";
$database_thatexclients = "myexclients";
$username_thatexclients = "root";
$password_thatexclients = "";
$thatexclients = mysql_connect($hostname_thatexclients, $username_thatexclients,   $password_thatexclients) or trigger_error(mysql_error(),E_USER_ERROR); 
set_time_limit ( 240 );




if($_FILES['yourpic']['size'] > 1) 
{
if($_FILES['yourpic']['size'] < 5000000) 
$newname = "image01.jpg";
$id = 0;
$query = ("SELECT * FROM clients WHERE  ID = (SELECT MAX(ID) FROM clients)") or die(mysql_error());
mysql_select_db($database_thatexclients, $thatexclients);
$Result2 = mysql_query($query, $thatexclients) or die(mysql_error());
While($row = mysql_fetch_array($Result2))
{
$id = $row["ID"];
$id = ($id + "1");
}  
mkdir(UPLOAD_DIR.$id, 0777, true) or die ("Could not make directory"); 
$idr = ($id.'/');  
move_uploaded_file($_FILES['yourpic']['tmp_name'],UPLOAD_DIR.$idr .$newname);// this one works  
}
else
{
$id = 0;
}

?>

任何帮助将是巨大的:)

Answer 1

好吧，代码必须一直是狡猾的.jpeg图片，代码看起来一直在令人尴尬地工作着