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[英]Return multiple XML nodes and Custom parent tag using FLWOR XQuery
[英]Using xquery FLWOR expressions to find multiple “where” restrictions
我正在努力找到在休斯顿工作的员工,但项目所在的部门并不在休斯顿。 我试图在FLWOR表达式的这个示例之后对表达式进行建模,但是查询没有返回任何内容,它应该返回结果。
编辑:这是输入 。
xquery
let $doc := doc("~path/company.xml")
for $e in $doc//employee,
$d in $doc//department,
$p in $doc//projects
where $d/locations[location!="Houston"]
and $p/project[plocations="Houston"]
return <e>{$e/fname}{$e/lname}{$e/address}</e>
/
一个for
子句就足够了; 否则,你会多次迭代所有员工:
let $doc := doc(...)
for $e in $doc//employee
let $p := $doc//project[@pnumber = $e/projects/worksOn/@pno]
where $p[plocation = 'Houston']
and $doc//department[@dno = $p/@controllingDepartment]
[not(locations/location = 'Houston')]
return <e>{ $e/fname }{ $e/lname }{ $e/address }</e>
单个XPath 2.0表达式可以选择所有想要的员工:
/*/employees
/*[projects/*/@pno
=
/*/projects/*
[plocation eq 'Houston'
and
boolean
(for $dn in @controllingDepartment
return
/*/departments/*
[@dno eq $dn
and
not(locations/location
=
'Houston'
)
]
)
]/@pnumber
]
错字: and $p/project[plocation="Houston"]
你有一个“s”太多了:是plocations
。
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