[英]java AudioInputStream AudioSystem.write to pipe length error
[英]Java Length Unlimited AudioInputStream
我有一堆代码,在运行时会产生过程声音。 不幸的是,它只持续几秒钟。 理想情况下,它将一直运行直到我告诉它停止为止。 我不是在谈论循环,生成它的算法目前提供2 ^ 64个样本,因此在可预见的将来它不会用完。 AudioInputStream的构造函数接受第三个输入,理想情况下,我可以将其删除。 我只能提供大量的信息,但这似乎是错误的解决方法。
我考虑过使用SourceDataLine,但理想情况下该算法将称为按需算法,而不是先行编写路径。 有什么想法吗?
看来我已经回答了我自己的问题。
经过进一步的研究,使用SourceDataLine
是SourceDataLine
的方法,因为如果您给予足够的使用,它将阻塞。
抱歉,缺少适当的Javadoc。
class SoundPlayer
{
// plays an InputStream for a given number of samples, length
public static void play(InputStream stream, float sampleRate, int sampleSize, int length) throws LineUnavailableException
{
// you can specify whatever format you want...I just don't need much flexibility here
AudioFormat format = new AudioFormat(sampleRate, sampleSize, 1, false, true);
AudioInputStream audioStream = new AudioInputStream(stream, format, length);
Clip clip = AudioSystem.getClip();
clip.open(audioStream);
clip.start();
}
public static void play(InputStream stream, float sampleRate, int sampleSize) throws LineUnavailableException
{
AudioFormat format = new AudioFormat(sampleRate, sampleSize, 1, false, true);
SourceDataLine line = AudioSystem.getSourceDataLine(format);
line.open(format);
line.start();
// if you wanted to block, you could just run the loop in here
SoundThread soundThread = new SoundThread(stream, line);
soundThread.start();
}
private static class SoundThread extends Thread
{
private static final int buffersize = 1024;
private InputStream stream;
private SourceDataLine line;
SoundThread(InputStream stream, SourceDataLine line)
{
this.stream = stream;
this.line = line;
}
public void run()
{
byte[] b = new byte[buffersize];
// you could, of course, have a way of stopping this...
for (;;)
{
stream.read(b);
line.write(b, 0, buffersize);
}
}
}
}
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