[英]Split string with ' in C#
如何分割这个字串
1014,'0,1031,1032,1034,1035,1036',0,0,1,1,0,1,0,-1,1
并得到这个字符串数组作为结果
1014
'0,1031,1032,1034,1035,1036'
0
0
1
1
0
1
0
-1
1
在C#中
我相信这个正则表达式应该为您提供所需的东西:
('(?:[^']|'')*'|[^',\r\n]*)(,|\r\n?|\n)?
编辑:
有关其工作方式的快速代码段:
var rx = new Regex("('(?:[^']|'')*'|[^',\r\n]*)(,|\r\n?|\n)?");
var text= "1014,'0,1031,1032,1034,1035,1036',0,0,1,1,0,1,0,-1,1";
var matches = rx.Matches(text);
foreach (Match match in matches)
{
System.Console.WriteLine(match.Groups[1].ToString());
}
这段代码一点也不漂亮,但是可以用。 :)(不适用于字符串中的多个“字符串”。)
void Main()
{
string stuff = "1014,'0,1031,1032,1034,1035,1036',0,0,1,1,0,1,0,-1,1";
List<string> newStuff = new List<string>();
var extract = stuff.Substring(stuff.IndexOf('\''), stuff.IndexOf('\'', stuff.IndexOf('\'') + 1) - stuff.IndexOf('\'') + 1);
var oldExtract = extract;
extract = extract.Replace(',',';');
stuff = stuff.Replace(oldExtract, extract);
newStuff.AddRange(stuff.Split(new[] {','}));
var newList = newStuff;
for(var i = 0; i < newList.Count; i++)
newList[i] = newList[i].Replace(';',',');
// And newList will be in the format you specified, but in a list..
}
尝试这个,
string line ="1014,'0,1031,1032,1034,1035,1036',0,0,1,1,0,1,0,-1,1" ;
var values = Regex.Matches(line, "(?:'(?<m>[^']*)')|(?<m>[^,]+)");
foreach (Match value in values) {
Console.WriteLine(value.Groups["m"].Value);
}
首先在'
(单引号)上分割字符串,然后使用comma
(,)。
您不需要解析器,也不需要正则表达式。 这是一个非常简单的版本,可以完美运行:
var splits = input
.Split('\'')
.SelectMany(
(s,i) => (i%2==0)
? s.Split(new[]{','}, StringSplitOptions.RemoveEmptyEntries)
: new[]{ "'" + s + "'"}
);
这正是@AVD + @Rawling所描述的...在'
分割,只分割“偶数”结果,然后合并。
using System;
using System.IO;
using Microsoft.VisualBasic.FileIO; //Microsoft.VisualBasic.dll
public class Sample {
static void Main(){
string data = "1014,'0,1031,1032,1034,1035,1036',0,0,1,1,0,1,0,-1,1";
string[] fields = null;
data = data.Replace('\'', '"');
using(var csvReader = new TextFieldParser(new StringReader(data))){
csvReader.SetDelimiters(new string[] {","});
csvReader.HasFieldsEnclosedInQuotes = true;
fields = csvReader.ReadFields();
}
foreach(var item in fields){
Console.WriteLine("{0}",item);
}
}
}
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