获取mySQL存储过程将导致另一个存储过程

Question

我需要一个存储过程的示例，该示例使用另外两个存储过程（甚至仅一个）的结果，其中结果用作组合存储过程中的表。 我可能会从那里拿走。

网络上的示例（多个站点）和php.net上的详细信息都过于简单。

基本问题可以在这里看到：

SELECT ttd.person_id, weight, min(test_date)
FROM (
  CALL get_team_member_body_stats(1) AS tbs,   
  CALL get_team_member_first_last_test_date(1) AS ttd
  WHERE tbs.person_id = ttd.person_id
  AND (tbs.test_date = ttd.first_test OR tbs.test_date = ttd.last_test)
  GROUP BY ttd.person_id;
END

谢谢你的帮助。 昨天和今天，在网上搜索和实验中，我已经奋战了好几个小时。

细节：

表格1

存储过程get_team_member_body_stats（IN team_id INT）工作于5个表（人，团队，人_队，body_stats，person_body_stats），并产生：

person_id | body_stats_id | weight | test_date |   
  2         2               200      2011-01-01  
  4         3               250      2011-01-01  
  1         5               145      2011-03-01 
  2         6               210.4    2011-03-01 
  5         7               290      2011-03-01 
  1         8               140      2011-04-01 
  1         9               135      2011-05-01 
  4         11              245      2011-05-01 

表2

存储过程get_team_member_first_last_test_date（IN team_id INT）在相同的表上工作并产生：

person_id | first_test | last_test

1           2011-03-01   2011-05-01
2           2011-01-01   2011-03-01
4           2011-01-01   2011-05-01
5           2011-03-01   2011-03-01

目标是加入这些并产生：

表3

person_id | first_weight | last_weight

1           145            135
2           200            210.4 
4           250            245
5           290            290

谢谢

Answer 1

（在这个社区中，并且因为我找不到使用其他存储过程的结果集作为新选择表中的表的存储过程的任何示例），mysql要么不支持它，要么很难做到我希望能做到。

因此，我没有调用存储过程，而是将查询复制到了此最终过程中。

DELIMITER $$

    CREATE DEFINER=`root`@`localhost` PROCEDURE `get_team_stats_change`(
        IN team_id INT
    )
    BEGIN
    SELECT SUM(start_weight) AS start_weight, 
        SUM(start_body_fat) AS start_body_fat, 
        SUM(current_weight) AS current_weight,
        SUM(current_body_fat) AS current_body_fat,
        SUM(weight_change) AS weight_change, 
        SUM(body_fat_change) AS body_fat_change FROM (
    SELECT ls.person_id, 
        fs.weight AS start_weight, fs.body_fat AS start_body_fat, 
        ls.weight AS current_weight, ls.body_fat AS current_body_fat,
        fs.weight - ls.weight AS weight_change, fs.body_fat - ls.body_fat AS body_fat_change
    FROM
    (SELECT ttd.person_id, bs.weight, bs.body_fat, bs.test_date
    FROM body_stats AS bs
    JOIN
        ((SELECT pbs.person_id,  min(bs.test_date)  AS first_test, max(bs.test_date) AS last_test   
        FROM body_stats AS bs,
            person_body_stats AS pbs,
            team_member AS tm,
            team AS t
        WHERE t.team_id = team_id
        AND tm.team_id = t.team_id
        AND tm.person_id = pbs.person_id
        AND pbs.body_stats_id = bs.body_stats_id
        AND tm.start_date  bs.test_date
        AND bs.test_date >= t.starting_date
        GROUP BY person_id) AS ttd,
        person_body_stats AS pbs)
    ON bs.test_date = ttd.first_test 
        AND pbs.person_id = ttd.person_id 
        AND pbs.body_stats_id = bs.body_stats_id) AS fs,

    (SELECT ttd.person_id, bs.weight, bs.body_fat, bs.test_date
    FROM body_stats AS bs
    JOIN
        ((SELECT pbs.person_id,  min(bs.test_date)  AS first_test, max(bs.test_date) AS last_test   
        FROM body_stats AS bs,
            person_body_stats AS pbs,
            team_member AS tm,
            team AS t
        WHERE t.team_id = team_id
        AND tm.team_id = t.team_id
        AND tm.person_id = pbs.person_id
        AND pbs.body_stats_id = bs.body_stats_id
        AND tm.start_date  bs.test_date
        AND bs.test_date >= t.starting_date
        GROUP BY person_id) AS ttd,
        person_body_stats AS pbs)
    ON bs.test_date = ttd.last_test 
        AND pbs.person_id = ttd.person_id 
        AND pbs.body_stats_id = bs.body_stats_id) AS ls
        WHERE ls.person_id = fs.person_id
       ) AS delta;
    END

Answer 2

我不知道从合并到临时表或视图中的5个表中获得这些结果有多容易，但是从本质上讲，以下操作应与您当前尝试使用3个存储过程的操作相同。

SELECT person_id
       , (SELECT weight 
          FROM   FiveTablesResult 
          WHERE  person_id = ftr.person_id 
                 AND test_date = (SELECT MIN(test_date) 
                                  FROM   FiveTablesResult 
                                  WHERE  person_id = ftr.person_id)
         ) AS first_weight
       , (SELECT weight 
          FROM   FiveTablesResult 
          WHERE  person_id = ftr.person_id 
                 AND test_date = (SELECT MAX(test_date) 
                                  FROM   FiveTablesResult 
                                  WHERE  person_id = ftr.person_id)
         ) AS last_weight
FROM   FiveTablesResult ftr

请注意，还有优化的空间，但让我们先获取正确的结果