[英]How to Copy Image File from Gallery to another folder without changing its modified date programmatically?
[英]How to Copy Image File from Gallery to another folder programmatically in Android
我想从图库中选择图像并将其复制到 SDCard 中的其他文件夹中。
从图库中选择图像的代码
Intent photoPickerIntent = new Intent(Intent.ACTION_PICK);
photoPickerIntent.setType("image/*");
startActivityForResult(photoPickerIntent, REQUEST_CODE_CHOOSE_PICTURE_FROM_GALLARY);
我得到content://media/external/images/media/681
这个 URI onActivityResult。
我想复制图片,
表单path ="content://media/external/images/media/681
到path = "file:///mnt/sdcard/sharedresources/
Android中sdcard的这个路径。
这个怎么做?
感谢所有人......工作代码在这里......
private OnClickListener photoAlbumListener = new OnClickListener(){
@Override
public void onClick(View arg0) {
Intent photoPickerIntent = new Intent(Intent.ACTION_GET_CONTENT);
imagepath = Environment.getExternalStorageDirectory()+"/sharedresources/"+HelperFunctions.getDateTimeForFileName()+".png";
uriImagePath = Uri.fromFile(new File(imagepath));
photoPickerIntent.setType("image/*");
photoPickerIntent.putExtra(MediaStore.EXTRA_OUTPUT,uriImagePath);
photoPickerIntent.putExtra("outputFormat",Bitmap.CompressFormat.PNG.name());
photoPickerIntent.putExtra("return-data", true);
startActivityForResult(photoPickerIntent, REQUEST_CODE_CHOOSE_PICTURE_FROM_GALLARY);
}
};
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
if (resultCode == RESULT_OK) {
switch(requestCode){
case 22:
Log.d("onActivityResult","uriImagePath Gallary :"+data.getData().toString());
Intent intentGallary = new Intent(mContext, ShareInfoActivity.class);
intentGallary.putExtra(IMAGE_DATA, uriImagePath);
intentGallary.putExtra(TYPE, "photo");
File f = new File(imagepath);
if (!f.exists())
{
try {
f.createNewFile();
copyFile(new File(getRealPathFromURI(data.getData())), f);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
startActivity(intentGallary);
finish();
break;
}
}
}
private void copyFile(File sourceFile, File destFile) throws IOException {
if (!sourceFile.exists()) {
return;
}
FileChannel source = null;
FileChannel destination = null;
source = new FileInputStream(sourceFile).getChannel();
destination = new FileOutputStream(destFile).getChannel();
if (destination != null && source != null) {
destination.transferFrom(source, 0, source.size());
}
if (source != null) {
source.close();
}
if (destination != null) {
destination.close();
}
}
private String getRealPathFromURI(Uri contentUri) {
String[] proj = { MediaStore.Video.Media.DATA };
Cursor cursor = managedQuery(contentUri, proj, null, null, null);
int column_index = cursor.getColumnIndexOrThrow(MediaStore.Images.Media.DATA);
cursor.moveToFirst();
return cursor.getString(column_index);
}
OutputStream out;
String root = Environment.getExternalStorageDirectory().getAbsolutePath()+"/";
File createDir = new File(root+"Folder Name"+File.separator);
if(!createDir.exists()) {
createDir.mkdir();
}
File file = new File(root + "Folder Name" + File.separator +"Name of File");
file.createNewFile();
out = new FileOutputStream(file);
out.write(data);
out.close();
希望它会帮助你
一种解决方案可以是,
1) 从所选文件的 inputStream 中读取字节。
我在ActivityResult上得到“content://media/external/images/media/681”这个URI。 你可以通过查询你得到的这个 Uri 来获取文件名。 得到它的 inputStream。 将其读入字节[]。
干得好/
Uri u = Uri.Parse("content://media/external/images/media/681");
Cursor cursor = contentResolver.query(u, null, null, null, null); 有一个列名“_data”,它将返回文件名,您可以从文件名创建输入流,
您现在可以读取此输入流
byte data=new byte[fis.available()];
fis.read(data);
所以你有数据(字节数组)和图像字节
2)在sdcard上创建一个文件,并用第一步中的字节[]写入。
File file=new File(fileOnSD.getAbsolutePath() +"your foldername", fileName);
FileOutputStream fout=new FileOutputStream(file, false);
fout.write(data);
作为查询方法中已有的文件名,请在此处使用相同的文件名。
正在阅读此链接,他们在这里讨论了在 Java 中复制文件的四种方法,因此也与 android 相关。
尽管作者得出结论,使用@Prashant 回答中使用的“频道”是最好的方法,但您甚至可以探索其他方法。
(我试过前两个,他们都找到了)
尽管我已经对@AAnkit 的答案投了赞成票,但我还是借用了并继续修改了一些项目。 他提到使用Cursor
但如果没有适当的说明,新手可能会感到困惑。
我认为这比投票最多的答案更简单。
String mCurrentPhotoPath = "";
private File createImageFile() throws IOException {
String timeStamp = new SimpleDateFormat("yyyyMMdd_HHmmss").format(new Date());
String imageFileName = "JPEG_" + timeStamp + "_";
File storageDir = getExternalFilesDir(Environment.DIRECTORY_PICTURES);
File image = File.createTempFile(
imageFileName, /* prefix */
".jpg", /* suffix */
storageDir /* directory */
);
mCurrentPhotoPath = image.getAbsolutePath();
return image;
}
/*Then I proceed to select from gallery and when its done selecting it calls back the onActivityResult where I do some magic*/
private void snapOrSelectPicture() {
Intent takePictureIntent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
if (takePictureIntent.resolveActivity(getPackageManager()) != null) {
File photoFile = null;
try {
photoFile = createImageFile();
} catch (IOException ex) {
ex.printStackTrace();
}
if (photoFile != null) {
Uri photoURI = FileProvider.getUriForFile(this,
"com.example.android.fileprovider",
photoFile);
takePictureIntent.putExtra(MediaStore.EXTRA_OUTPUT, photoURI);
startActivityForResult(Intent.createChooser(takePictureIntent, "SELECT FILE"), 1001);
}
}
}
@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
if (resultCode == RESULT_OK) {
try {
/*data.getDataString() contains your path="content://media/external/images/media/681 */
Uri u = Uri.parse(data.getDataString());
Cursor cursor = getContentResolver().query(u, null, null, null, null);
cursor.moveToFirst();
File doc = new File(cursor.getString(cursor.getColumnIndex("_data")));
File dnote = new File(mCurrentPhotoPath);
FileOutputStream fout = new FileOutputStream(dnote, false);
fout.write(Files.toByteArray(doc));
} catch (Exception e) {
e.printStackTrace();
}
}
}
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