Java Xpath表达式

Question

我有以下XML：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<application xmlns="http://research.sun.com/wadl/2006/10">
<doc xmlns:jersey="http://jersey.dev.java.net/" 
     jersey:generatedBy="Jersey: 1.0.2 02/11/2009 07:45 PM"/>
<resources base="http://localhost:8080/stock/">
    <resource path="categories"> (<<---I want to get here)
        <method id="getCategoriesResource" name="GET">

而且我想获取resource/@path的值，所以我有以下Java代码：

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
factory.setNamespaceAware(true); // never forget this!
DocumentBuilder builder = factory.newDocumentBuilder();
// get the xml to parse from URI
Document doc = builder.parse(serviceUri + "application.wadl"); 
XPathFactory xfactory = XPathFactory.newInstance();
XPath xpath = xfactory.newXPath();
XPathExpression expression = 
        xpath.compile("/application/resources/resource/@path");
this.baseUri = (String) expression.evaluate(doc, XPathConstants.STRING);

使用此XPath表达式，结果（ baseUri ）始终是空字符串（ "" ）。

Answer 1

节点不在空字符串名称空间中，您必须指定它： /wadl:application/wadl:resources/wadl:resource/@path 。 另外，您应该在XPath引擎名称空间上下文中注册名称空间。

这是工作示例：

    xpath.setNamespaceContext(new NamespaceContext()
    {
        @Override
        public String getNamespaceURI(final String prefix)
        {
            if(prefix.equals("wadl"))
                return "http://research.sun.com/wadl/2006/10";
            else
                return null;
        }

        @Override
        public String getPrefix(final String namespaceURI)
        {
            throw new UnsupportedOperationException();
        }

        @Override
        public Iterator getPrefixes(final String namespaceURI)
        {
            throw new UnsupportedOperationException();
        }
    });
    XPathExpression expression = xpath.compile("/wadl:application/wadl:resources/wadl:resource/@path");