日期范围内每天的棘手mysql计数

Question

我在获取以下记录时遇到麻烦

TABLE
id | holiday_From | holiday_To
1  | 2012-01-02   | 2012-01-03
1  | 2012-01-11   | 2012-01-16
1  | 2012-01-08   | 2012-01-22
1  | 2012-01-29   | 2012-01-30
1  | 2012-01-08   | 2012-01-11

我正在尝试获取给定月份的假期-例如

BETWEEN "2012-01-01" AND "2012-01-31"

有类似的帖子，但我无法根据我的需要进行调整

RESULT
day (within range) | count() //number of ppl on holiday
DATE               | 3

例如

SAMPLE OUTPUT
2012-01-02 | 1
2012-01-03 | 1
2012-01-08 | 2
2012-01-09 | 2
2012-01-10 | 2
2012-01-11 | 3
2012-01-12 | 2
2012-01-13 | 2
2012-01-14 | 2
2012-01-15 | 2
2012-01-16 | 2
......

换句话说，我正在尝试获取在特定日期找到记录的次数。 即1号，2号，3号等有多少人在度假。

并非每个月的每一天都在表格中

有任何想法吗？

ps这就是我已经拥有的（我在黑暗中拍摄）

SELECT h.holiday_From, h.holiday_To, COUNT( * )
FROM holiday h
JOIN holiday ho ON h.holiday_From
BETWEEN DATE( "2012-01-01" )
AND IF( DATE( "2012-01-31" ) , DATE( "2012-01-31" ) , DATE( "2012-01-01" ) )
GROUP BY h.holiday_From, h.holiday_To

Answer 1

拜托，不要害怕:)）

基于日期范围内的生成天数

select d.everyday, count(*) from (select @rownum:=@rownum+1, date('2012-01-01') + interval (@rownum-1) day everyday from
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t2,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t3,
(SELECT @rownum:=0) r WHERE @rownum < DAY(LAST_DAY('2012-01-01'))) d, tablename tbl WHERE d.everyday>=tbl.hFrom AND d.everyday<tbl.hTo GROUP BY d.everyday

结果：

2012-01-02  1
2012-01-08  2
2012-01-09  2
2012-01-10  2
2012-01-11  2
2012-01-12  2
2012-01-13  2
2012-01-14  2
2012-01-15  2
2012-01-16  1
2012-01-17  1
2012-01-18  1
2012-01-19  1
2012-01-20  1
2012-01-21  1
2012-01-29  1

ps：我将列重命名为hFrom和hTo

pps：日期范围的更新变体

select d.everyday, count(*) from (select @rownum:=@rownum+1, date('2012-01-01') + interval (@rownum - 1) day everyday from
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t2,
(select 0 union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) t3,
(SELECT @rownum:=0) r WHERE @rownum <= DATEDIFF('2012-01-11','2012-01-01')) d, `test` tbl WHERE d.everyday BETWEEN tbl.hFrom AND tbl.hTo GROUP BY d.everyday

已更新 -所有工会都缺少2号。 它不会对任何事物产生重大影响。

Answer 2

你尝试过这样的事情吗？

http://dev.mysql.com/doc/refman/5.5/zh-CN/date-and-time-functions.html#function_last-day

此功能将为您提供每月的最后一天，而不管涉及的变量如month / leapyear / etc...。

那可能是您遇到的问题。 还不清楚...

SELECT h.holiday_From, h.holiday_To, COUNT( * )
FROM holiday h
JOIN holiday ho 
    ON h.holiday_From BETWEEN DATE( "2012-01-01" ) AND LAST_DAY("2012-01-01" )
GROUP BY h.holiday_From, h.holiday_To