繁体   English   中英

如何在iOS中处理1到3个手指轻扫手势

[英]how to handle 1 to 3 fingers swipe gesture in iOS

我使用以下代码处理我的代码中的1个手指滑动:

UISwipeGestureRecognizer *swipe = [[UISwipeGestureRecognizer alloc] initWithTarget:self action:@selector(handleViewsSwipe:)];
    [swipe setDirection:UISwipeGestureRecognizerDirectionLeft];
    [swipe setDelaysTouchesBegan:YES];
    [[self view] addGestureRecognizer:swipe];

我知道我可以添加以下行以使其处理2个手指滑动:

 [swipe setNumberOfTouchesRequired:2];

但是,当我添加上面的代码时,由于现在所需的触摸次数为2,因此不再检测到手指滑动。我可以做些什么来使我的代码适用于1,2或3个手指滑动?

我尝试使用以下代码,但这不符合我的要求。

UIPanGestureRecognizer *panRecognizer = [[UIPanGestureRecognizer alloc] initWithTarget:self action:@selector(handleViewsSwipe:)];
    [panRecognizer setMinimumNumberOfTouches:1];
    [panRecognizer setMaximumNumberOfTouches:3];
    [panRecognizer setDelaysTouchesBegan:YES];
    [[self view] addGestureRecognizer:panRecognizer];
    [panRecognizer release];

谢谢。

在handleViewsSwipe中,您可以从手势识别器获取numberOfTouches属性。

- (void)handleViewsSwipe:(UISwipeGestureRecognizer *)recognizer {
    NSUInteger touches = recognizer.numberOfTouches;
    switch (touches) {
        case 1:
            break;
        case 2:
            break;
        case 3:
            break;
        default:
            break;
    }
}

根据您获得的触摸次数,只需切换相同的方法即可。

在视图中添加三个滑动手势识别器:

for (int i = 1; i <= 3; ++i) {
    UISwipeGestureRecognizer *swipe = [[UISwipeGestureRecognizer alloc] initWithTarget:self action:@selector(handleViewsSwipe:)];
    swipe.numberOfTouchesRequired = i;
    swipe.direction = UISwipeGestureRecognizerDirectionLeft;
    swipe.delaysTouchesBegan = YES;
    [self.view addGestureRecognizer:swipe];
}

为我工作。

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM