具有结构指针数组的嵌套结构

Question

主要结构

typedef struct {
   uint8 u8Status;
   uint8 u8NeighborTableEntries;
   uint8 u8StartIndex;
   uint8 u8NeighborTableListCount;
   /* Rest of the message is variable length */
   ZPS_tsAplZdpDiscNtEntry* pNetworkTableList;
                                              //pNetworkTableList is a pointer to 
                                              //the first   
                                              //entry in the list of reported
                                              //Neighbour table entries
 } ZPS_tsAplZdpMgmtLqiRsp;


typedef struct
{
   uint64 u64ExtPanId;
   uint64 u64ExtendedAddress;
   uint16 u16NwkAddr;
   uint8 u8LinkQuality;
   uint8 u8Depth;
   union
   {
     struct
     {
       unsigned u2DeviceType:2;
       unsigned u2RxOnWhenIdle:2;
       unsigned u2Relationship:3;
       unsigned u1Reserved1:1;
       unsigned u2PermitJoining:2;
       unsigned u6Reserved2:6;
    } ;
    uint8 au8Field[2];
 } uAncAttrs;
} ZPS_tsAplZdpDiscNtEntry;

我已经定义了ZPS_tsAplZdpMgmtLqiRsp * pointer;

这似乎还可以。

pointer->u8Status
pointer->u8NeighborTableEntries
pointer->u8StartIndex
pointer->u8NeighborTableListCount

但是我如何访问ZPS_tsAplZdpDiscNtEntry结构内的那些值

Answer 1

您可以使用以下pointer->pNetworkTableList访问数组： pointer->pNetworkTableList以便从那里可以访问结构的所有元素。

例如，访问索引为0的元素的u64ExtPanId：

pointer->pNetworkTableList[0].u64ExtPanId = 1232;

Answer 2

您有指针，但是没有结构本身的实例。 做下一个：

ZPS_tsAplZdpMgmtLqiRsp *pointer = (ZPS_tsAplZdpMgmtLqiRsp *)malloc(sizeof(ZPS_tsAplZdpMgmtLqiRsp));

...是的，您还应该为pNetworkTableList分配内存：

pointer->pNetworkTableList = (ZPS_tsAplZdpDiscNtEntry *)malloc(sizeof(ZPS_tsAplZdpDiscNtEntry));

那你可能

做

 pointer->pNetworkTableList->u8Status = 12; 

等等。

别忘了做

free(pointer->pNetworkTableList);
free(pointer);

在工作的最后。