[英]I want to change background color after clicking using javascript
以下是我的代码:
<table border="0" align="center" cellpadding="0" cellspacing="0" class="grid_table">
<tr class="grid_caption"><td class="grid_caption">Customer Name</td></tr>
<? if(count($arrResult) > 0) { ?>
<? foreach($arrResult as $row) { ?>
<tr class="grid_row" ><td class="grid_row" onClick="javascript:return selectCustomer(this,<?=$row['customer_id']?>);"><?=HTMLVarConv($row['Name'])?></td></tr>
<? } ?>
<? } ?>
</table>
在这里,我得到了客户列表,但是当我单击此客户名称时,其背景颜色应更改..这是我的javascript函数
function selectCustomer(row, id) {
alert(row);
var mark_color = '#fdf5d2' //'#c1c1ff'
var current_row = '#aad4f0' //'#e8e8e8'
if (row.style.backgroundColor == current_row) {
row.style.backgroundColor = mark_color;
}
else if (row.style.backgroundColor == mark_color) {
row.style.backgroundColor = current_row;
}
$("#editCustomer").attr("src","editcustomer.php?customer_id="+id+"&showmenu=0");
$("#ajaxList").show();
return;
}
但没有改变什么问题? 请帮我
由于您标记了“ jquery”,为什么不使用它而不是内联onclick
处理程序? 它可以很简单: http : //jsfiddle.net/t7vj5/ 。
$("td.grid_row").click(function() {
$(this).toggleClass("selected");
$("#editCustomer").attr("src", "editcustomer.php");
$("#ajaxList").show();
return false;
});
和CSS:
td.grid_row {
background-color: #fdf5d2;
}
td.grid_row.selected {
background-color: #aad4f0;
}
只要确保在创建行之后执行JavaScript,或将其包装在$(document).ready(function() { ... })
。
$('.grid_row').click(function(){
$('.grid_row').css("background-color","#aad4f0");
$(this).css("background-color","#fdf5d2");
});
编辑:哦,您可以删除onclick =函数上面的行对于您想要做的事情就足够了,只要存在类rowrow。
单击后,它将颜色更改为#fdf5d2,而单击另一行时,将所有其他单元格的颜色更改为#aad4f0。 如果您不希望颜色变回来,请删除第一行
这是完美的:Css ::
.grid_row
{
padding: 3px;
border-right: 1px solid #849AAA;
border-bottom: 1px solid #849AAA;
vertical-align:top;
}
.evn
{
padding: 3px;
border-right: 1px solid #849AAA;
border-bottom: 1px solid #849AAA;
vertical-align:top;
background-color: white;
/*document.body.style.cursor = 'wait';*/
cursor: pointer;
}
.selevn
{
padding: 3px;
border-right: 1px solid #849AAA;
border-bottom: 1px solid #849AAA;
vertical-align:top;
background-color: silver;
cursor: pointer;
}
以下是我的Javascript代码:-
<script type="text/javascript">
var prevRow = null;
function selectCustomer(it,id) {
if (it.className.substring(0, 3) == "sel")
{
it.className = it.className.substring(3, 6);
prevRow = null;
}
else
{
it.className = "sel" + it.className;
if (prevRow != null)
{
prevRow.className = prevRow.className.substring(3, 6);
}
prevRow = it;
}
$("#editCustomer").attr("src","editcustomer.php?customer_id="+id+"&showmenu=0");
$("#ajaxList").show();
return ;
}
这是我的代码:
<table border="0" align="center" cellpadding="0" cellspacing="0" class="grid_table">
<tr class="grid_caption"><td class="grid_caption">Customer Name</td></tr>
<? if(count($arrResult) > 0) { ?>
<? foreach($arrResult as $row) { ?>
<tr class="evn" onClick="javascript:return selectCustomer(this,<?=$row['customer_id']?>);" ><td class="grid_row" id="<?= $row['customer_id']?>" ><?=HTMLVarConv($row['Name'])?></td></tr>
<? } ?>
<? } ?>
</table>
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