[英]Database Connection in Zend Framework
我是ZF的新手。 我在这里将我的application.ini
编码为:
[development]
includePaths.library = APPLICATION_PATH "/../library"
bootstrap.path = APPLICATION_PATH "/Bootstrap.php"
bootstrap.class = "Bootstrap"
appnamespace = "Application"
resources.frontController.controllerDirectory = APPLICATION_PATH "/controllers"
resources.frontController.params.displayExceptions = 0
resources.view.encoding = "utf-8"
resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts"
phpSettings.display_startup_errors = 1
phpSettings.display_errors = 1
phpSettings.display_startup_errors = 1
phpSettings.display_errors = 1
resources.frontController.params.displayExceptions = 1
resources.DB.adapter = "pdo_mysql"
resources.DB.params.host = "localhost"
resources.DB.params.username = "root"
resources.DB.params.password = ""
resources.DB.params.dbname = "xyz"
这是我的index.php
defined('APPLICATION_PATH')
|| define('APPLICATION_PATH', realpath(dirname(__FILE__) . '/../application'));
// Define application environment
defined('APPLICATION_ENV')
|| define('APPLICATION_ENV', (getenv('APPLICATION_ENV') ? getenv('APPLICATION_ENV') : 'development'));
// Ensure library/ is on include_path
set_include_path(implode(PATH_SEPARATOR, array(
realpath(APPLICATION_PATH . '/../library'),
get_include_path(),
)));
/** Zend_Application */
require_once 'Zend/Application.php';
// Create application, bootstrap, and run
$application = new Zend_Application(
APPLICATION_ENV,
APPLICATION_PATH . '/configs/application.ini'
);
$application->bootstrap()->run();
这是我的bootstrap.php
class Bootstrap extends Zend_Application_Bootstrap_Bootstrap{
protected function _initDoctype(){
$this->bootstrap('view');
$view = $this->getResource('view');
$view->doctype(Zend_View_Helper_Doctype::HTML5);
}
}
现在首先我像这样进行连接
$params = array('host' => 'localhost',
'username' => 'root',
'password' => '',
'dbname' => 'xyz'
);
$DB = new Zend_Db_Adapter_Pdo_Mysql($params);
$DB->setFetchMode(Zend_Db::FETCH_OBJ);
Zend_Registry::set('DB',$DB);
稍后在查询中,我使用它来检索记录:
$registry = Zend_Registry::getInstance();
$DB = $registry['DB']; and than my query
现在,当我更改了我的设置方式(包括bootstrap和application.ini
如何实现与我相同的设置? 因为在我的应用程序中,一切都是这样。
现在我收到此错误。
注意:未定义索引:DB in
C:\\ xampp \\ htdocs \\ xyz \\ application \\ controllers \\ LoginController.php,第59行
致命错误:在第64行的C:\\ xampp \\ htdocs \\ xyz \\ application \\ controllers \\ LoginController.php中的非对象上调用成员函数select()
第59行是
$registry = Zend_Registry::getInstance();
$DB = $registry['DB'];
第64行是
$select = $DB->select()
->from(array('p' => 'phone_service'))
->join(array('u' => 'user_preferences'), 'u.phone_service_id = p.phone_service_id')
->where('u.user_preferences_name = ?', 'is_user_package_active')
->where('p.user_id = ?', $user_id);
已编辑
if($result->isValid()){
$data = $authAdapter->getResultRowObject(null,'password');
$auth->getStorage()->write($data);
$this->_redirect('/login/controlpannel');}
现在我的查询在这里找不到$user_id
$data = Zend_Auth::getInstance()->getStorage()->read();
$user_id = $data->user_id;
$DB = Zend_Db_Table_Abstract::getDefaultAdapter();
$select = $DB->select()
->from(array('p' => 'phone_service'))
->join(array('u' => 'user_preferences'), 'u.phone_service_id = p.phone_service_id')
->where('u.user_preferences_name = ?', 'is_user_package_active')
->where('p.user_id = ?', $user_id);
这就是为什么我得到这个错误
注意:尝试获取我的.phtml文件中非对象的属性
使用时默认
resources.db.*
在application.ini中,将设置具有这些设置的默认适配器(默认情况下,在Zend_Db_Table中使用)。
由于默认情况下该适配器已经在Zend_db_Table_Abstract中注册为默认适配器,因此访问它就像使用以下命令一样容易:
$db = Zend_Db_Table_Abstract::getDefaultAdapter();
获得它的另一种方法是从bootstrap-instance获取它,它类似于以下内容(根据参考手册 ):
$front = Zend_Controller_Front::getInstance();
$bootstrapResource = $front->getParam('boostrap')->getPluginResource('db');
$db = $boostrapResource->getDbAdapter();
Zend_Registry是一个对象,因此您应该这样做:
$registry = Zend_Registry::getInstance();
$DB = $registry->DB;
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