[英]Need help on aggregating data into a view (SQL Server)
我是使用视图的新手,但是我不确定要使用视图是否可以做。
第一个表是我导入到SQL中的原始数据文件。 我创建的视图仅包含fruit和amount_from_us列,但在弄清楚如何在其中包括数量时遇到了麻烦。 通常,我会使用where子句,但是我不知道如何在选择其他数据的同时做到这一点。
这是我到目前为止的内容:
CREATE VIEW fruit_summary AS
SELECT fruit
, SUM(amount) AS amount
FROM original_table
WHERE bought_from_us = 'yes'
GROUP BY fruit
这使我得到了水果列和amount_from_us列。 但是,我对如何在那里获取日期和总额一无所知。 使用视图甚至可以做到这一点还是我应该只创建一个表并使用联接?
尝试:
SELECT fruit,
[date],
SUM(amount) AS amount,
SUM(case when bought_from_us = 'yes' then amount else 0 end)
AS amount_from_us
FROM original_table
GROUP BY fruit, [date]
create table #original_table
(
[date] datetime,
fruit varchar(50),
amount money,
bought_from_us char(3)
)
insert #original_table([date], fruit, amount, bought_from_us)
values ('01/18/2012', 'Apple', 10, 0);
insert #original_table([date], fruit, amount, bought_from_us)
values ('01/18/2012', 'Apple', 25, 'yes');
insert #original_table([date], fruit, amount, bought_from_us)
values ('01/18/2012', 'Orange', 32, 0);
insert #original_table([date], fruit, amount, bought_from_us)
values ('01/18/2012', 'Banana', 8, 0);
insert #original_table([date], fruit, amount, bought_from_us)
values ('01/18/2012', 'Banana', 235, 'yes');
insert #original_table([date], fruit, amount, bought_from_us)
values ('01/17/2012', 'Apple', 65, 0);
insert #original_table([date], fruit, amount, bought_from_us)
values ('01/17/2012', 'Apple', 4, 'yes');
insert #original_table([date], fruit, amount, bought_from_us)
values ('01/17/2012', 'Orange', 56, 0);
insert #original_table([date], fruit, amount, bought_from_us)
values ('01/17/2012', 'Orange', 95, 0);
您要求的结果非常复杂。 要获取最后一条记录,Jan-17 Banana 0 0,您需要以下内容:
with date_fruit_table as
(
select date_table.[date], fruit_table.fruit
from
(select distinct fruit from #original_table) as fruit_table,
(select distinct [date] from #original_table) as date_table
)
select date_fruit_table.[date], date_fruit_table.fruit,
SUM(isnull(#original_table.amount, 0)) as amount,
SUM(case #original_table.bought_from_us when 'yes' then #original_table.amount else 0 end) as amount_from_us
from date_fruit_table
left outer join #original_table on #original_table.fruit = date_fruit_table.fruit
and #original_table.[date] = date_fruit_table.[date]
group by date_fruit_table.[date], date_fruit_table.fruit
order by date_fruit_table.[date] desc
SELECT fruit
, SUM(amount) AS amount
, SUM(amount_from_us) AS amount_from_us
, [Date]
FROM original_table
WHERE bought_from_us = 'yes'
GROUP BY fruit, [Date]
很抱歉我的第一个答案,现在我意识到您需要什么:
with CTE_fruit as (
SELECT fruit, date, SUM(amount) AS amount, NULL AS amountUS
FROM original_table
GROUP BY fruit, date
union
SELECT fruit, date, NULL AS amount, SUM(amount) AS amountUS
FROM original_table
WHERE bought_from_us = 'yes'
GROUP BY fruit, date
)
select fruit, date, sum(amount), sum(amountUS) from CTE_fruit
GROUP BY fruit, date
我认为这会起作用
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