[英]Java: How to split a string with delimiter by limiting the number of characters in a string?
[英]Java: How to split a string by a number of characters?
我试图在网上搜索以解决这个问题,但我没有找到任何东西。
我写了下面的抽象代码来解释我在问什么:
String text = "how are you?";
String[] textArray= text.splitByNumber(4); //this method is what I'm asking
textArray[0]; //it contains "how "
textArray[1]; //it contains "are "
textArray[2]; //it contains "you?"
splitByNumber 方法每 4 个字符拆分字符串“text”。 我如何创建此方法?
非常感谢
我认为他想要的是将字符串拆分为大小为 4 的子字符串。然后我会在循环中执行此操作:
List<String> strings = new ArrayList<String>();
int index = 0;
while (index < text.length()) {
strings.add(text.substring(index, Math.min(index + 4,text.length())));
index += 4;
}
使用番石榴:
Iterable<String> result = Splitter.fixedLength(4).split("how are you?");
String[] parts = Iterables.toArray(result, String.class);
正则表达式呢?
public static String[] splitByNumber(String str, int size) {
return (size<1 || str==null) ? null : str.split("(?<=\\G.{"+size+"})");
}
试试这个
String text = "how are you?";
String array[] = text.split(" ");
或者你可以在下面使用它
List<String> list= new ArrayList<String>();
int index = 0;
while (index<text.length()) {
list.add(text.substring(index, Math.min(index+4,text.length()));
index=index+4;
}
快速破解
private String[] splitByNumber(String s, int size) {
if(s == null || size <= 0)
return null;
int chunks = s.length() / size + ((s.length() % size > 0) ? 1 : 0);
String[] arr = new String[chunks];
for(int i = 0, j = 0, l = s.length(); i < l; i += size, j++)
arr[j] = s.substring(i, Math.min(l, i + size));
return arr;
}
使用简单的 java 原语和循环。
private static String[] splitByNumber(String text, int number) {
int inLength = text.length();
int arLength = inLength / number;
int left=inLength%number;
if(left>0){++arLength;}
String ar[] = new String[arLength];
String tempText=text;
for (int x = 0; x < arLength; ++x) {
if(tempText.length()>number){
ar[x]=tempText.substring(0, number);
tempText=tempText.substring(number);
}else{
ar[x]=tempText;
}
}
return ar;
}
用法: String ar[]=splitByNumber("nalaka", 2);
我不认为有一个开箱即用的解决方案,但我会做这样的事情:
private String[] splitByNumber(String s, int chunkSize){
int chunkCount = (s.length() / chunkSize) + (s.length() % chunkSize == 0 ? 0 : 1);
String[] returnVal = new String[chunkCount];
for(int i=0;i<chunkCount;i++){
returnVal[i] = s.substring(i*chunkSize, Math.min((i+1)*chunkSize-1, s.length());
}
return returnVal;
}
用法是:
String[] textArray = splitByNumber(text, 4);
编辑:子字符串实际上不应超过字符串长度。
这是使用 Java8 流的简洁实现:
String text = "how are you?";
final AtomicInteger counter = new AtomicInteger(0);
Collection<String> strings = text.chars()
.mapToObj(i -> String.valueOf((char)i) )
.collect(Collectors.groupingBy(it -> counter.getAndIncrement() / 4
,Collectors.joining()))
.values();
输出:
[how , are , you?]
这是我能想到的最简单的解决方案..试试这个
public static String[] splitString(String str) {
if(str == null) return null;
List<String> list = new ArrayList<String>();
for(int i=0;i < str.length();i=i+4){
int endindex = Math.min(i+4,str.length());
list.add(str.substring(i, endindex));
}
return list.toArray(new String[list.size()]);
}
试试这个解决方案,
public static String[]chunkStringByLength(String inputString, int numOfChar) {
if (inputString == null || numOfChar <= 0)
return null;
else if (inputString.length() == numOfChar)
return new String[]{
inputString
};
int chunkLen = (int)Math.ceil(inputString.length() / numOfChar);
String[]chunks = new String[chunkLen + 1];
for (int i = 0; i <= chunkLen; i++) {
int endLen = numOfChar;
if (i == chunkLen) {
endLen = inputString.length() % numOfChar;
}
chunks[i] = new String(inputString.getBytes(), i * numOfChar, endLen);
}
return chunks;
}
我的应用程序使用文本到语音! 这是我的算法,如果字符串长度小于限制,则按“点”分割并合并字符串
String[] text = sentence.split("\\.");
ArrayList<String> realText = sentenceSplitterWithCount(text);
函数sentenceSplitterWithCount:(我concanate string lf小于100个字符的长度,这取决于你)
private ArrayList<String> sentenceSplitterWithCount(String[] splittedWithDot){
ArrayList<String> newArticleArray = new ArrayList<>();
String item = "";
for(String sentence : splittedWithDot){
item += DataManager.setFirstCharCapitalize(sentence)+".";
if(item.length() > 100){
newArticleArray.add(item);
item = "";
}
}
for (String a : newArticleArray){
Log.d("tts", a);
}
return newArticleArray;
}
function setFirstCharCapitalize 只是大写第一个字母:我想,你不需要它,反正
public static String setFirstCharCapitalize(String input) {
if(input.length()>2) {
String k = checkStringStartWithSpace(input);
input = k.substring(0, 1).toUpperCase() + k.substring(1).toLowerCase();
}
return input;
}
您可以通过以下方式简单地将 String 拆分为 String 数组:
String[] parts = yourString.split(" ");
System.out.println(parts[0]);
System.out.println(parts[1]);
System.out.println(parts[2]);
输出:
how
are
you?
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