[英]how to fetch data from two table in cake php
这是动作网址
http:// localhost / carsdirectory / cars / home
cars_controller.php(控制器)
public function home(){
$this->set('latest_cars', $this->Car->find('all', array(
'order' => array(
'Car.modified DESC',
'Car.created Desc'
),
'limit' => '3'
)));
$this->set('galleries', $this->Gallery->find('all'));
}
car.php(模型)
public $hasMany = array(
'Gallery' => array(
'className' => 'Gallery',
'foreignKey' => 'car_id',
'dependent' => true
)
);
gallery.php(模型)
var $belongsTo = array(
'Car' => array(
'className' => 'Car',
'foreignKey' => 'car_id',
)
);
home.ctp(查看)
<?php foreach($latest_cars as $latest_car){ ?>
<img src="img/car-listings.jpg" /> // now it's static
<h4><?php echo $latest_car['Car']['car_name']; ?></h4> // it's dynamic it's coming car table
<span>$<?php echo $latest_car['Car']['car_price']; ?></span> // it's dynamic it's coming car table
<?php } ?>
我已经替换了那条线
<img src="img/car-listings.jpg" />
用那条线
<?php $this->Html->image('/media/filter/small/'.$latest_cars['Gallery']['dirname'].'/'.$latest_cars['Gallery']['basename']);?>
但我收到那个错误
未定义索引:图库[APP \\ views \\ cars \\ home.ctp,第226行]
<img src="img/car-listings.jpg" /> this line i want to make dynamic , so my question how to use join in cars_controller or any other idea and i want to fetch data from galleries table
这是画廊表结构
ID-1
基本名称-chrysanthemum_10.jpg
car_id-1
提前致谢
因此,您有一个Car
模型和一个Gallery
模型。 由于Gallery
具有car_id
属性,因此可以用来形成以下CakePHP 关联 :
画廊属于汽车
和
汽车hasOne画廊
您可以选择实际需要的关联,然后在模型中定义它们。 对于您的情况,您想在查询汽车时显示汽车的画廊,因此:
// in car.php
var $hasOne = 'Gallery';
然后,您可以选择是要使用Containable来控制将哪些关联包含在查询中,还是仅使用recursive
方式将所有关联包括在内:
// in cars_controller.php
$this->set('latest_cars', $this->Car->find('all', array(
'recursive' => 1,
'order' => array(
'Car.modified DESC',
'Car.created Desc'
),
'limit' => '3'
)));
然后在您看来,使用$latest_car['Car']
访问汽车属性,并使用$latest_car['Gallery']
访问图库属性
编辑
如果Car
Many Gallery
,那么您应该期望这种结构:
[0] =>
Car => (first car)
Gallery =>
[0] => (first gallery of first car)
[1] => (second gallery of first car)
[1] =>
Car => (second car)
Gallery =>
[0] => (first gallery of second car)
etc.
因此,在您的视图中访问它:
<?php
foreach($latest_cars as $latest_car){
foreach ($latest_car['Gallery'] as $gallery)
echo $this->Html->image('/media/filter/small/'.$gallery['dirname'].'/'.$gallery['basename']);
?>
在Controller查找中使用join,根据需要指定字段
$results= $this->Car->find('all',
array('fields'=> array('Car.*','galleries.*'),
'joins'=> array(
array('table'=>'galleries', 'type'=>'inner',
'conditions'=>array('Car.car_id=galleries.car_id'))
))
)
在您的控制器文件中添加此行
$this->loadModel('Table');//table is your model name in singular
$this->set('table', $this->Table->find('all'));
您可以直接在视图中使用$ table,如果您与table有关系,则可以使用CakePHP提供的默认关系
谢谢
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