调用Soap WebService从带有轴的Java客户端返回对象列表

Question

我对Web服务感到生气。

我有一个非常简单的soap webservice：

@Remote
public interface StudentService
{
public String sayHello();
public List<Student> getStudents();
}

和

@Stateless
@WebService
public class StudentServiceImpl implements StudentService
{

@Override
public String sayHello()
{
    return "Hello World";
}

public List<Student> getStudents()
{
    List<Student> students = new ArrayList<Student>();

    Student st1 = new Student();
    st1.setMatricule(1234);
    st1.setName("student1");
    students.add(st1);

    Student st2 = new Student();
    st2.setMatricule(5678);
    st2.setName("student2");
    students.add(st2);

    return students;
    }
}

和

public class Student implements Serializable
{
private static final long serialVersionUID = 8286393242028201686L;

private int matricule; 
private String name;

public int getMatricule()
{
    return matricule;
}
public void setMatricule(int matricule)
{
    this.matricule = matricule;
}

public String getName()
{
    return name;
}
public void setName(String name)
{
    this.name = name;
}
}

我在glassfish 3.1下部署该服务。

使用glassfish控制台，它可以正常工作。

<?xml version="1.0" encoding="UTF-8"?>
<S:Envelope xmlns:S="http://schemas.xmlsoap.org/soap/envelope/">
    <S:Body>
        <ns2:getStudentsResponse xmlns:ns2="http://services.tuto.java.com/">
            <return>
                <matricule>1234</matricule>
                <name>student1</name>
            </return>
            <return>
                <matricule>5678</matricule>
                <name>student2</name>
            </return>
        </ns2:getStudentsResponse>
    </S:Body>
</S:Envelope>

使用php也是可行的（对于这两种方法）。

现在有了一个Java客户端：

import javax.xml.namespace.QName;

import org.apache.axis.client.Call;
import org.apache.axis.client.Service;

public class Client
{
public static void main(String[] args) throws Exception
{
    String endPoint = "http://localhost:8080/StudentServiceImplService/StudentServiceImpl";

    Service service = new Service();
    Call call = (Call) service.createCall();
    call.setTargetEndpointAddress(new java.net.URL(endPoint));
    call.setOperationName(new QName("http://services.tuto.java.com/","sayHello"));

    System.out.println(call.invoke(new Object[0]));

    Service service2 = new Service();
    Call call2 = (Call) service2.createCall();
    call2.setTargetEndpointAddress(new java.net.URL(endPoint));
    call2.setOperationName(new QName("http://services.tuto.java.com/","getStudents"));

    System.out.println(call2.invoke(new Object[0]));
    }
}

第一次通话有效，但第二次通话无效。

Hello World
12-mars-2012 14:53:23 org.apache.axis.client.Call invoke
GRAVE: Exception:
org.xml.sax.SAXException: SimpleDeserializer encountered a child element, which is NOT expected, in something it was trying to deserialize.
at org.apache.axis.encoding.ser.SimpleDeserializer.onStartChild(SimpleDeserializer.java:145)
at org.apache.axis.encoding.DeserializationContext.startElement(DeserializationContext.java:1035)
at org.apache.axis.message.SAX2EventRecorder.replay(SAX2EventRecorder.java:165)
at org.apache.axis.message.MessageElement.publishToHandler(MessageElement.java:1141)
at org.apache.axis.message.RPCElement.deserialize(RPCElement.java:345)
at org.apache.axis.message.RPCElement.getParams(RPCElement.java:384)
at org.apache.axis.client.Call.invoke(Call.java:2467)
at org.apache.axis.client.Call.invoke(Call.java:2366)
at org.apache.axis.client.Call.invoke(Call.java:1812)
at Client.main(Client.java:24)

我能做什么 ？

经过大量时间在互联网上搜索并尝试使用不同的解决方案后，仍然无法正常工作...

有一个简单的解决方案吗？

谢谢。

编辑：

还尝试过：

public class SoapClient
{
public static void main(String[] args) throws Exception
{
    SOAPMappingRegistry smr = new SOAPMappingRegistry();
    BeanSerializer beanSer = new BeanSerializer();
    smr.mapTypes(Constants.NS_URI_SOAP_ENC,new QName("http://services.tuto.java.com/", "StudentServiceImplService"),Student.class, beanSer, beanSer);       

    Call call = new Call();
    call.setSOAPMappingRegistry(smr);
    call.setEncodingStyleURI(Constants.NS_URI_SOAP_ENC);

    call.setTargetObjectURI("http://services.tuto.java.com/");
    call.setMethodName("getStudents");

    Response resp;
    try
    {
        resp = call.invoke(new URL("http://8h9l45j:8080/StudentServiceImplService/StudentServiceImpl"), "");
    }
    catch (SOAPException e)
    {
        System.err.println("Caught SOAPException (" +
          e.getFaultCode() + "): " + e.getMessage());
        return;
    }

    if (!resp.generatedFault())
    {
        Parameter ret = resp.getReturnValue();
        Object value = ret.getValue();
        if ( value != null )
        {
            String[] tlist = (String[])value;
            System.out.println();
            for ( int i = 0; i < tlist.length; i++ )
                System.out.println(tlist[i]);
        }
    }
    else
    {
        Fault fault = resp.getFault();
        System.err.println("Generated fault: ");
        System.out.println ("  Fault Code   = "
                            + fault.getFaultCode());
        System.out.println ("  Fault String = "
                            + fault.getFaultString());
    }
}

结果如下：

Caught SOAPException (SOAP-ENV:Client): No Deserializer found to deserialize a ':return' using encoding style 'http://schemas.xmlsoap.org/soap/encoding/'.

Answer 1

使用soap客户进行响应的第一要素。

问题出在maptypes命名空间：没有命名空间

所以现在，我有

    smr.mapTypes(Constants.NS_URI_SOAP_ENC,new QName("","student"),Student.class, null, new BeanSerializer());  
    smr.mapTypes(Constants.NS_URI_SOAP_ENC,new QName("","matricule"),Integer.class, null, new IntDeserializer());   
    smr.mapTypes(Constants.NS_URI_SOAP_ENC,new QName("","name"),Integer.class, null, new StringDeserializer()); 

并添加

@XmlRootElement(name = "Student",namespace="http://services.tuto.java.com/")

到学生班

<?xml version="1.0" encoding="UTF-8"?>
<S:Envelope xmlns:S="http://schemas.xmlsoap.org/soap/envelope/">
    <S:Body>
        <ns2:getStudentsResponse xmlns:ns2="http://services.tuto.java.com/">
            <student>
                <matricule>1236</matricule>
                <name>student1</name>
            </student>
            <student>
                <matricule>5678</matricule>
                <name>student2</name>
            </student>
        </ns2:getStudentsResponse>
    </S:Body>
</S:Envelope>

轴客户端：

 public class AxisClient
{
    public static void main(String[] args) throws Exception
    {
    String endPoint = "http://localhost:8080/StudentServiceImplService/StudentServiceImpl";
    Service service2 = new Service();
    Call call2 = (Call) service2.createCall();
    call2.setTargetEndpointAddress(new java.net.URL(endPoint));
    call2.setOperationName(new QName("http://services.tuto.java.com/","getStudents"));
    call2.setReturnType(new QName("","student"), Student.class);
    call2.setReturnType(new QName("", "student"));
    call2.registerTypeMapping(Student.class, new QName("", "student"), null,new BeanDeserializerFactory(Student.class, new QName("", "student")));
    List<Student> students = (List<Student>) call2.invoke(new Object[0]);
    for (Student student : students)
    {
        System.out.println(student);
    }
    }
 }

给所有学生：

Student [matricule=1236, name=student1]
Student [matricule=5678, name=student2]

axis2客户端：

public static void main(String[] args) throws Exception
{
    String endPoint = "http://localhost:8080/StudentServiceImplService/StudentServiceImpl";

    ServiceClient sc = new ServiceClient();

    Options opts = new Options();
    opts.setTo(new EndpointReference("http://localhost:8080/StudentServiceImplService/StudentServiceImpl"));
    sc.setOptions(opts);

    OMFactory fac = OMAbstractFactory.getOMFactory();
    OMNamespace omNs = fac.createOMNamespace("http://services.tuto.java.com/","ns1");

    OMElement method = fac.createOMElement("getStudents", omNs);
    OMElement res = sc.sendReceive(method);
    System.out.println(res);

    Iterator<OMElement> it = res.getChildElements();
    while(it.hasNext())
    {
        System.out.println(it.next());
    }
}

给予

<ns2:getStudentsResponse xmlns:ns2="http://services.tuto.java.com/"><student><matricule>1236</matricule><name>student1</name></student><student><matricule>5678</matricule><name>student2</name></student></ns2:getStudentsResponse>
<student><matricule>1236</matricule><name>student1</name></student>
<student><matricule>5678</matricule><name>student2</name></student>

但是我不知道如何反序列化。

我尝试过

Student student = (Student) BeanUtil.deserialize(Student.class,res,new DefaultObjectSupplier(),null);

但是给我

Student [matricule=null, name=null]

我能怎么做 ？

遗留问题：

• 不知道如何对轴进行相同操作-确定之前请参阅-/轴2
• “ resp”（肥皂客户端） 仅包含第一个学生

Answer 2

你能不能像这样进入WSDL？

http://localhost:8080/StudentServiceImplService/StudentServiceImpl?wsdl

然后使用axis wsdl2java让Axis为您创建客户端代码（它将具有所有正确的类型映射和名称空间）？

Answer 3

您正在使用什么SOAP绑定样式RPC / DOCUMENT ？ 如果使用的是RPC，则请求和响应将被编码和处理，Axis2不支持RPC编码格式消息。 尝试使用DOCUMENT SOAP绑定样式。 （我应该在评论中写上，请忍受）

请参阅https://stackoverflow.com/a/9598193/752129