带Scribe的OAuth Vimeo（Java）

Question

注意：仅通过将我定向到一个很好地说明如何与Web服务进行交互的位置，您就可以为我提供帮助。 但是，非常感谢您对此特定问题的帮助！

我很难理解OAuth的工作原理。 我正在尝试开发一个桌面应用程序，该应用程序会将一堆视频上传到Vimeo上的帐户。 我尝试过修改Scribe API及其示例 。 不幸的是，抄写员没有Vimeo示例，因此我一直在尝试更改Facebook示例以使其适用于Vimeo。 关于这一切如何工作的信息很少（我已经能够1：找到，2：理解）。 就代码和错误而言，这是我所拥有的：

public class VimeoTest
{
  private static final String NETWORK_NAME = "Vimeo";
  private static final Token EMPTY_TOKEN = null;

  public static void main(String[] args)
  {
    // Replace these with your own api key and secret
    String apiKey = "MYAPIKEY";
    String apiSecret = "MYAPISECRET";
    OAuthService service = new ServiceBuilder()
                                  .provider(VimeoApi.class)
                                  .apiKey(apiKey)
                                  .apiSecret(apiSecret)
                                  .build();
    Scanner in = new Scanner(System.in);

    System.out.println("=== " + NETWORK_NAME + "'s OAuth Workflow ===");
    System.out.println();
    OAuthRequest orequest = new OAuthRequest(Verb.GET, "http://vimeo.com/api/rest/v2");
    orequest.addQuerystringParameter("method", "vimeo.test.null");
    Response send = orequest.send();
    System.out.println(send.getBody());

    // Obtain the Authorization URL
    System.out.println("Fetching the Authorization URL...");
    Token requestToken = service.getRequestToken();

    //Breaks on the line above.
    //But I think it's because the orequest.send() returned a 100 error code

    String authorizationUrl = service.getAuthorizationUrl(requestToken);
    System.out.println("Got the Authorization URL!");
    System.out.println("Now go and authorize Scribe here:");

    //I do NOT want to have to do this. Is there any other way I can have this authorize without going to a web browser to do this?

    System.out.println(authorizationUrl);
    System.out.println("And paste the authorization code here");
    System.out.print(">>");
    Verifier verifier = new Verifier(in.nextLine());
    System.out.println();

这是输出和错误：

=== Vimeo's OAuth Workflow ===

1.0
<?xml version="1.0" encoding="utf-8"?>
<rsp generated_in="0.0069" stat="fail">
  <err code="100" expl="The API key passed was not valid" msg="Invalid API Key" />
</rsp>
Fetching the Authorization URL...
Exception in thread "main" java.lang.NoClassDefFoundError: org/apache/commons/codec/binary/Base64
    at org.scribe.services.HMACSha1SignatureService.doSign(HMACSha1SignatureService.java:47)
    at org.scribe.services.HMACSha1SignatureService.getSignature(HMACSha1SignatureService.java:33)
    at org.scribe.oauth.OAuth10aServiceImpl.getSignature(OAuth10aServiceImpl.java:118)
    at org.scribe.oauth.OAuth10aServiceImpl.addOAuthParams(OAuth10aServiceImpl.java:63)
    at org.scribe.oauth.OAuth10aServiceImpl.getRequestToken(OAuth10aServiceImpl.java:43)
    at autouploadermodel.VimeoTest.main(VimeoTest.java:38)
Caused by: java.lang.ClassNotFoundException: org.apache.commons.codec.binary.Base64
    at java.net.URLClassLoader$1.run(URLClassLoader.java:366)
    at java.net.URLClassLoader$1.run(URLClassLoader.java:355)
    at java.security.AccessController.doPrivileged(Native Method)
    at java.net.URLClassLoader.findClass(URLClassLoader.java:354)
    at java.lang.ClassLoader.loadClass(ClassLoader.java:423)
    at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:308)
    at java.lang.ClassLoader.loadClass(ClassLoader.java:356)
    ... 6 more
Java Result: 1

无论如何，我敢打赌这确实很简单，但我只是不了解如何与Web服务接口。 谢谢你的帮助！

Answer 1

您需要在类路径中包含apache commons编解码器