如何使用 smack Java 获取 IQ 标签？

Question

实际上，问题是当我的 xmpp 客户端发送朋友邀请，然后接收方批准邀请时，openfire 服务器再次向发起方/邀请发送方推送订阅包进行授权，这就是为什么我想通过自动阻止这种情况使用 IQ 标签对其进行过滤，然后自动对其进行授权。

但是使用 PacketListener，我无法获得 IQ 标签...

我怎样才能做到这一点？

@Override
public void processPacket(Packet packet) {
    Log.i(TAG, "SECOND subscription");
    Log.d(TAG, "SECOND: "+packet.toXML());
    if (packet instanceof Presence) {
        Presence p = (Presence) packet;
        Log.d(TAG, "TYPE-Presence: "+p.getType());
        if (p.getType() != Presence.Type.subscribe)
        return;
        String from = p.getFrom();
        Log.d(TAG, "PACKET from: "+from);
        Notification notification = new Notification(android.R.drawable.stat_notify_more, mService.getString(
                R.string.AcceptContactRequest, from), System.currentTimeMillis());
        notification.flags = Notification.FLAG_AUTO_CANCEL;
        Intent intent = new Intent(mService, Subscription.class);
        intent.setData(Contact.makeXmppUri(from));
        notification.setLatestEventInfo(mService, from, mService
                .getString(R.string.AcceptContactRequestFrom, from), PendingIntent.getActivity(mService, 0,
                        intent, PendingIntent.FLAG_ONE_SHOT));
        int id = p.hashCode();
        mService.sendNotification(id, notification);
    }
}

Answer 1

可以使用“IQTypeFilter”过滤器过滤掉传入的 IQ。 这是说明该方法的示例代码。

    connection.connect();

    /* packet listener: listen for incoming messages of type IQ on the connection (whatever the buddy) */
    PacketFilter filter = new IQTypeFilter(IQ.Type.SET); // or IQ.Type.GET etc. according to what you like to filter. 

    connection.addPacketListener(new PacketListener() { 
        public void processPacket(Packet packet) {
            // HERE YOU PUT YOUR CODE TO HANDLE THE IQ MESSAGE
        }
    }, filter);  

Answer 2

您可以使用 IQTypeFilter 来实现它，它是 IQ 数据包类型的过滤器：

public final class IQTypeFilter extends FlexibleStanzaTypeFilter<IQ> {

    public static final StanzaFilter GET = new IQTypeFilter(Type.get);
    public static final StanzaFilter SET = new IQTypeFilter(Type.set);
    public static final StanzaFilter RESULT = new IQTypeFilter(Type.result);
    public static final StanzaFilter ERROR = new IQTypeFilter(Type.error);
    public static final StanzaFilter GET_OR_SET = new OrFilter(GET, SET);

    private final IQ.Type type;

    private IQTypeFilter(IQ.Type type) {
        super(IQ.class);
        this.type = Objects.requireNonNull(type, "Type must not be null");
    }

    @Override
    protected boolean acceptSpecific(IQ iq) {
        return iq.getType() == type;
    }

    @Override
    public String toString() {
        return getClass().getSimpleName() + ": type=" + type;
    }

Answer 3

如 Javadoc 中所定义，IQTypeFilter 是 IQ 数据包类型的过滤器。 仅当数据包是 IQ 数据包并且它与构造函数中提供的类型匹配时才返回 true。 有一些使用IQTypeFilter的例子

Answer 4

这是使用Smack 4.3.4的更新答案。 我明确地发表了评论，以使我的代码清晰。

   /**
     *  packet listener: listen for incoming messages of whith IQ as elelement
     *  exmaple of IQ : <iq from="mbula@domain" to="dedi@domain" type="get" >.......</iq>
     */
    public static void listenToStanzas(AbstractXMPPConnection connection){

        // IQ filter type. it can Be GET, SET, RESULT, ERROR
        //in my case I filter SET IQs
        StanzaFilter filter =  IQTypeFilter.SET;

        connection.addSyncStanzaListener(new StanzaListener() {
            @Override
            public void processStanza(Stanza packet) {
                //Put yoour code Here
            }
        }, filter);
    }