[英]Using ORDER BY clause inside GROUP_CONCAT function in SQLite
我认为我不能在GROUP_CONCAT
函数内使用ORDER BY
子句。
有谁知道在SQLite
完成此行为的棘手方法?
我以前看过这个问题 。 但是我有一个复杂的查询。
我的陈述如下:
SELECT
c.col1, c.col3, m.col3, m.col4,
count(m.col1), count(re.col2) AS cnt,
GROUP_CONCAT(p.col1 ORDER BY p.col1) AS "Group1",
GROUP_CONCAT(p.col2 ORDER BY p.col1) AS "Group2",
GROUP_CONCAT(CASE WHEN con.col3 is null THEN p.col1 ELSE con.col3 END),
con.col4, con.col5, p.col3
FROM t1 re
INNER JOIN t2 c ON (re.col1 = c.col1)
INNER JOIN t3 p ON (re.col2 = p.col1)
LEFT JOIN t4 con ON (con.col1 = p.col2)
INNER JOIN t5 m ON (m.col1 = c.col5)
GROUP BY re.col1
Group1
和Group2
来自同一表,但列不同:我想通过Group2
保留Group1
的顺序:
table t3
+------+------+
| col1 | col2 |
+------+------+
| 1 | A |
| 2 | B |
| 3 | C |
| 4 | D |
| 5 | E |
+------+------+
因此,如果Group1
看起来像这样2,1,3
Group2
应该看起来像这样B,A,C
SQLite在GROUP_CONCAT
内不支持ORDER BY
,但是您实际上可以伪造它:
GROUP_CONCAT(list_order || ':' || value)
然后,您需要将结果拆分为代码,以获取排序和值。
为了避免任何不确定性,您可以使用递归CTE,如下所示:
sqlite> create table t3(pos,col1,col2);
sqlite> insert into t3 values(1,2,'B'),(2,1,'A'),(3,5,'E');
sqlite> select * from t3;
1|2|B
2|1|A
3|5|E
sqlite>
with
sorted(pos,c1,c2) as (
select row_number() over (order by t3.pos), -- sorting by first column's value
t3.col1, t3.col2
from t3
),
concat(pos,c1,c2) as (
select sorted.pos,sorted.c1,sorted.c2 -- starting with values for first position
from sorted
where sorted.pos=1
union all
select sorted.pos,
concat.c1||','||sorted.c1, -- adding next value from col1
concat.c2||','||sorted.c2 -- adding next value from col2
from concat
join sorted
on concat.pos+1 = sorted.pos -- going through subsequent positions
)
select c1, c2
from concat
order by pos desc
limit 1; -- order by desc limit 1 means 'take the row with largest number'
2,1,5|B,A,E
尽管非常复杂,但此解决方案可确保正确排序,并且可以轻松扩展更多列。 排序列可能有间隙- sorted
CTE会使其变成适当的整数序列。
请注意, row_number() over (order by...)
可能需要支持窗口功能的最新版本的sqlite。
那这样的东西呢?
SELECT
col1, col3, col3, col4,
count(col1), count(re.col2) AS cnt,
GROUP_CONCAT(p.col1) AS "Group1",
GROUP_CONCAT(p.col2) AS "Group2",
GROUP_CONCAT(CASE WHEN con.col3 is null THEN p.col1 ELSE con.col3 END),
con.col4, con.col5, p.col3
FROM (
SELECT
*
FROM t1 re
INNER JOIN t2 c ON (re.col1 = c.col1)
INNER JOIN t3 p ON (re.col2 = p.col1)
LEFT JOIN t4 con ON (con.col1 = p.col2)
INNER JOIN t5 m ON (m.col1 = c.col5)
ORDER BY
p.col1 ASC,
p.col2 ASC
)
GROUP BY re.col1
我还没有测试过,但是如果您可以共享一些数据...
我已经尝试过了,这可以使工作
SELECT
c.col1, c.col3, m.col3, m.col4,
count(m.col1), count(re.col2) AS cnt,
GROUP_CONCAT(p.col1 ORDER BY p.col1) AS "Group1",
GROUP_CONCAT(p.col2 ORDER BY p.col1) AS "Group2",
GROUP_CONCAT(CASE WHEN con.col3 is null THEN p.col1 ELSE con.col3 END),
con.col4, con.col5, p.col3
FROM t1 re
INNER JOIN t2 c ON (re.col1 = c.col1)
INNER JOIN (
SELECT col1, col2, col3, col4, col5 FROM t3 ORDER BY col1
) AS p ON (re.col2 = p.col1)
LEFT JOIN t4 con ON (con.col1 = p.col2)
INNER JOIN t5 m ON (m.col1 = c.col5)
GROUP BY re.col1
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