[英]Semi-complicated result set in sql query
我有这样的user
表
FIRSTNAME | LASTNAME | ID |
--------------------------------
James | Hay | 1 |
Other | Person | 2 |
我也有这样的attendance
表
EVENTID | USERID | ATTENDANCE | STATUS |
-----------------------------------------------
1 1 True 3
2 1 False 1
3 1 False 3
1 2 False 1
2 2 True 3
3 2 True 3
基本上,当邀请用户参加活动时,会在attendance
表中添加一行,该行具有事件ID,其用户ID,错误出席率和状态0。
状态只是他们反应的指标
0 = No Response
1 = Said No
2 = Said Yes
3 = Said yes and seats confirmed
我想从查询这两个表中得到的最终结果非常复杂,我无法弄清楚该怎么做。
我想得到这样的结果
NAME | % of saying YES to an RSVP | % of attending after saying yes
-------------------------------------------------------------------------------
James Hay | 66 | 50
Other Person | 66 | 100
我确定您可以算出这些数字的获得方式,但请解释一下,James Hay的2(3)个活动的邀请率为3(是)。 所以说“是”的百分比是66。在他说“是”的2个指标中,他只参加了1/2,所以说“是”之后的出席百分比是50%
由于我无法直言不讳,因此在正确的轨道上进行任何推动将不胜感激。
编辑:
同样非常重要的一点是,我希望结果包含数据库中的每个用户,即使他们的attendance
表中有0行。
select
u.firstname, u.lastname
-- said yes, as percentage
,floor(100.0
* count(case when a.status in (2,3) then 1 end)
/ count(u.id)) yes
-- attended after saying yes, as percentage
,floor(100.0
* count(case when a.status in (2,3) and attendance='true' then 1 end)
/ nullif(count(case when a.status in (2,3) then 1 end),0)) attendance
--,count(u.id) rsvp -- total invites
from users u
left join attendance a on a.userid = u.id
group by u.firstname, u.lastname
注意:对于特殊情况(用户从未收到邀请),统计信息显示为0%和NULL。
术语解释:
count(case when a.status in (2,3) then 1 end)
count(u.id)
1
(不重要) count(case when a.status in (2,3) and attendance='true' then 1 end)
SELECT A.NAME,B.PERCENTAGE_YES_RSVP,B.PERCENTAGE_AFTER_YES
FROM
(
SELECT U.ID AS ID,U.FIRSTNAME+''+U.LASTNAME AS NAME
FROM USERS U
) A,
(
SELECT A.USERID,A.PERCENTAGE_YES_RSVP,B.PERCENTAGE_AFTER_YES
FROM
(
SELECT B.USERID,ROUND((CAST(B.COUNT_YES_RSVP AS FLOAT)/B.TOTAL_COUNT)*100,0) AS PERCENTAGE_YES_RSVP
FROM
(SELECT A.USERID,
SUM(CASE WHEN A.STATUS=3 THEN 1 END)AS COUNT_YES_RSVP,
COUNT(*) AS TOTAL_COUNT
FROM ATTENDANCE A
GROUP BY A.USERID
) B
) A,
(
SELECT C.USERID,(CAST(C.COUNT_AFTER_YES_RSVP AS FLOAT)/C.TOTAL_COUNT)*100 AS PERCENTAGE_AFTER_YES
FROM
(SELECT A.USERID,
SUM(CASE WHEN A.STATUS=3 AND A.ATTENDANCE='TRUE' THEN 1 END)AS COUNT_AFTER_YES_RSVP,
SUM(CASE WHEN A.STATUS=3 THEN 1 END) AS TOTAL_COUNT
FROM ATTENDANCE A
GROUP BY A.USERID
) C
)B
WHERE A.USERID=B.USERID
) B
WHERE A.ID = B.USERID;
编辑:
糟糕,忘记加入用户了:)
select firstname, lastname,
convert(decimal (5, 2), 1. * count(case when status in (2, 3) then 1 end) / count(*) * 100) SaidYes,
convert(decimal (5, 2), 1. * count(case when status in (2, 3) and attendance = 'True' then 1 end) / count(case when status in (2, 3) then 1 end) * 100) ActuallyAttended
from attendance a
join users u on a.userid = u.id
group by firstname, lastname
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