[英]How to filter an object based on a filter object
是否有一种简便的方法来仅使用filterInterface
定义的属性来过滤bigObject
,以将filteredObject
作为输出?
大对象具有很多属性,我想将信息分解为所需的属性(将其保存在某个地方,不想/不能保存整个对象)。
// My big object
var bigObject = {
prop1: {
prop2: {
prop3: 123,
prop4: 456,
prop5: "TEST"
},
prop6: 789,
prop7: "xxx"
},
prop8: 5.6,
prop9: 3
};
// My "interface" to filter the object
var filterInterface = {
prop1: {
prop2: {
prop3: true,
},
prop7: true
}
};
// My expected result, only the properties of
// big Object which match the interface
var filteredObject = {
prop1: {
prop2: {
prop3: 123,
},
prop7: "xxx"
}
};
简要地说,我希望这样的事情:
var filteredObject = {}
for (var key in filterObject) {
if (bigObject.hasOwnProperty(key)) {
filteredObject[key] = bigObject[key];
}
}
如果要“深度”过滤,请包括递归:
function filter(obj, filterObj) {
var newObj = {};
for (var key in filterObj) {
if (obj.hasOwnProperty(key)) {
if (typeof obj[key] == 'object' && typeof filterObj[key] == 'object') {
newObj[key] = filter(obj[key], filterObj[key]);
} else {
newObj[key] = obj[key];
}
}
}
return newObj;
}
var o = filter(bigObject, filterInterface);
alert(o.prop1.prop7); // 'xxx'
alert(o.prop1.prop9); // undefined
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.