[英]How to compare two rows from different tables and show the table values if the rows match?
[英]SQL compare two rows in a table to find how many values are different
我有下表用于存储用户数据:
例如
TABLE: users
COLUMNS:
...
maritalStatus (INT) - FK
gender (CHAR)
occupation (INT) - FK
...
现在我想比较这个表中的两个用户,看看有多少列匹配任何两个给定用户(比如用户 X 和用户 Y)
我通过 mySQL 存储过程分别获取每个值然后比较它们
例如
SELECT maritalStatus from users where userID = X INTO myVar1;
SELECT maritalStatus from users where userID = Y INTO myVar2;
IF myVar1 = myVar2 THEN
...
END IF;
使用 SQL 查询是否有更短的方法,我可以在其中比较表中的两行并查看哪些列不同? 我不需要知道它们实际上有多少不同,只需要知道它们是否包含相同的值。 此外,我只会比较选定的列,而不是用户表中的每一列。
这将选择用户x
和用户y
不相同的列数:
SELECT ( u1.martialStatus <> u2.martialStatus )
+ ( u1.gender <> u2.gender )
+ ( u1.occupation <> u2.occupation )
FROM
users u1,
users u2
WHERE u1.id = x
AND u2.id = y
你也可以用这个:
select
-- add other columns as needed
(a.lastname,a.gender)
= (b.lastname,a.gender) as similar,
a.lastname as a_lastname,
a.firstname as a_firstname,
a.age as a_age,
'x' as x,
b.lastname as b_lastname,
b.firstname as b_firstname,
b.age as b_age
from person a
cross join person b
where a.id = 1 and b.id = 2
输出:
SIMILAR A_LASTNAME A_FIRSTNAME A_AGE X B_LASTNAME B_FIRSTNAME B_AGE
1 Lennon John 40 x Lennon Julian 15
实时测试: http : //www.sqlfiddle.com/#!2/840a1/2
您可以使用group by
计算具有相同列的用户数:
select u1.maritalStatus
, u1.gender
, u1.occupation
, count(*)
from users u1
group by
u1.maritalStatus
, u1.gender
, u1.occupation
这是Peter Langs在PHP中提出的一个持续的例子:
$arr_cols = array('martialStatus', 'gender', 'occupation');
$arr_where = array();
$arr_select = array();
foreach($arr_cols as $h) {
$arr_having[] = "compare_{$h}";
$arr_select[] = "(u1.{$h} != u2.{$h}) AS compare_{$h}";
}
$str_having = implode(' + ', $arr_where);
$str_select = implode(', ', $arr_where);
$query = mysql_query("
SELECT {$str_select}
FROM users AS u1, users AS u2
WHERE u1.userid = {$int_userid_1} AND u2.userid = {$int_userid_2}
HAVING {$str_having} > 0
");
/* Having case can be removed if you need the row regardless. */
/* Afterwards you check these values: */
$row = mysql_fetch_assoc($query);
foreach($arr_cols as $h)
if ($row["compare_{$h}"])
echo "Found difference in column {$h}!";
我想,这可能对某人有所帮助。 目标:查找具有相同名称的行并使用旧记录更新新记录日期。 这可能是您必须为不同国家/地区复制新闻项目并与原始日期保持相同日期的条件。
CREATE TABLE `t` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `locale` varchar(10) DEFAULT 'en', `title` varchar(255) DEFAULT NULL, `slug` varchar(255) DEFAULT NULL, `body` text, `image` varchar(255) DEFAULT NULL, `thumb` varchar(255) DEFAULT NULL, `slug_title` varchar(255) DEFAULT NULL, `excerpt` text, `meta_title` varchar(200) DEFAULT NULL, `meta_description` varchar(160) DEFAULT NULL, `other_meta_tags` text, `read_count` int(10) DEFAULT '0', `status` varchar(20) DEFAULT NULL, `revised` text, `created` datetime DEFAULT NULL, `modified` datetime DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB AUTO_INCREMENT=20 DEFAULT CHARSET=utf8; INSERT INTO `t` (`id`, `locale`, `title`, `slug`, `body`, `image`, `thumb`, `slug_title`, `excerpt`, `meta_title`, `meta_description`, `other_meta_tags`, `read_count`, `status`, `revised`, `created`, `modified`) VALUES (2, 'en', 'A title once again', '/news/title-one-again', 'And the article body follows.', '/uploads/2014/11/telecommunications100x100.jpg', NULL, NULL, NULL, '', '', NULL, 0, 'Draft', NULL, '2014-09-22 12:26:17', '2014-10-23 10:13:21'), (3, 'en', 'A title once again', '/news/title-strikes-back', 'This is really exciting! Not.', '/uploads/2014/11/telecommunications100x100.jpg', NULL, NULL, NULL, '', '', NULL, 0, 'Unpublished', NULL, '2014-09-23 12:26:17', '2014-10-31 11:12:55'), (4, 'en_GB', 'test', '/news/test', 'test', '/uploads/2014/11/telecommunications100x100.jpg', NULL, NULL, NULL, '', '', NULL, 0, 'Published', NULL, '2014-10-23 10:14:30', '2014-10-23 10:14:30'); update t join t t2 on t.title = t2.title set t2.created = t.created where t.title = t2.title ;
更新t t ttt on t.title = t2.title set t2.created = t.created其中t.title = t2.title;
如果另一个Magento开发人员在这里找到他们的方式,这个Q / A的特定用途是比较表中的两个地址条目。 “Magento 1”会将相同的地址放入两次,唯一的区别是关键的entity_id
列和address_type
列(结算或发货)。
已经知道订单的entity_id
,使用它来获取与订单关联的开票和送货地址ID:
SELECT entity_id FROM sales_flat_order_address WHERE parent_id = 3137;
然后查看它们是否因订单而异:
SELECT a1.parent_id AS 'order_id'
, ( a1.street <> a2.street )
+ ( a1.city <> a2.city )
+ ( a1.postcode <> a2.postcode )
+ ( a1.region_id <> a2.region_id )
AS 'diffs'
FROM
sales_flat_order_address a1,
sales_flat_order_address a2
WHERE a1.entity_id = 6273
AND a2.entity_id = 6274
;
给出输出:
+----------+-------+
| order_id | diffs |
+----------+-------+
| 3137 | 0 |
+----------+-------+
如果有一种方法可以集体进行,那将是太棒了。
如果要找出表的两行中哪些列的值不同,可以使用以下查询:
SET @table_name = 'YOUR_TABLE_NAME';
SET @primary_column_name = 'PRIMARY_COLUMN_NAME';
SET @row1_id = '1234';
SET @row2_id = '1111';
SELECT CONCAT(
"SELECT ",
(
SELECT GROUP_CONCAT(" (CASE WHEN t1.", column_name, " != t2.", column_name ," THEN t1.", column_name, " ELSE '-' END) AS ", column_name ,"\n") AS all_column_names
FROM information_schema.columns WHERE table_name = @table_name AND table_schema = DATABASE()
), " FROM ",@table_name," AS t1 INNER JOIN Artiklar AS t2 ON(t1.",@primary_column_name," = '",@row1_id,"' AND t2.",@primary_column_name," = '",@row2_id,"')
UNION ALL
SELECT ",
(
SELECT GROUP_CONCAT(" (CASE WHEN t1.", column_name, " != t2.", column_name ," THEN t2.", column_name, " ELSE '-' END) AS ", column_name ,"\n") AS all_column_names
FROM information_schema.columns WHERE table_name = @table_name AND table_schema = DATABASE()
), " FROM ",@table_name," AS t1 INNER JOIN Artiklar AS t2 ON(t1.",@primary_column_name," = '",@row1_id,"' AND t2.",@primary_column_name," = '",@row2_id,"')
")
它将为您提供一个新的 SQL 查询,您可以运行该查询以查看哪些列在两行之间具有不同的值。
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