如何在Zend Framework 1.11中以JSON格式返回Application_Model

Question

我在我的视图中定义了一个名为Student的变量。 在我看来，如何将Student对象显示为JSON？

public function previewAction()
{
    // ... 
    $this->view->student = $student;
}

在我的Preview.phtml视图中，我具有以下内容：

<script>
    // this doesn't return the Application_Model as a JSON object in the html       
    var studentData = <?php echo Zend_Json::encode($this->student); ?>; 
</script>

Answer 1

将引号放在php标记周围

<script>
    // this doesn't return the Application_Model as a JSON object in the html       
    var studentData = "<?php echo Zend_Json::encode($this->student); ?>"; 
</script>