[英]What's wrong with this simple code?
我想比较下面的2个数组并找到不同之处。 键“ lead owner”和“ company”的值不同,但是当我比较这些数组时,它说只有“ company”值不同。 但是,当我为“潜在客户所有者”创建只有一个键/值对的2个新数组时,它可以正常工作。 我在犯错吗?
<?php
$arr1 = Array
(
"leadid" => "418176000000069007",
"smownerid" => "418176000000047003",
"lead owner" => "Amit Patil",
"company" => "SAM",
"first name" => "Test",
"last name" =>"Lead1",
"designation" => "call",
"email" => "",
"phone" => "958",
"fax" => "",
"mobile" => "",
"website" => "www.infosys.con",
"lead source" => "Cold Call",
"lead status" => "Contact in Future",
"industry" => "None",
"no of employees" => "45000",
"annual revenue" => "0",
"rating" => "Active",
"smcreatorid" => "418176000000047003",
"created by" => "Amit Patil",
"modifiedby" => "418176000000047003",
"modified by" => "Amit Patil",
"created time" => "2012-04-05 19:58:00",
"modified time" => "2012-05-02 08:51:08",
"street" => "",
"city" => "",
"state" => "",
"zip code" => "",
"country" => "",
"description" => "",
"skype id" => "",
"email opt out" => "false",
"salutation" => "Mr.",
"secondary email" => ""
);
$arr2 = Array
(
"leadid" => "418176000000069007",
"smownerid" => "418176000000047003",
"lead owner" => "Amit aaa",
"company" => "SAM A",
"first name" => "Test",
"last name" => "Lead1",
"designation" => "call",
"email" => "",
"phone" => "958",
"fax" => "",
"mobile" => "",
"website" => "www.infosys.con",
"lead_source" => "Cold Call",
"lead_status" => "Contact in Future",
"industry" => "None",
"no_of_employees" => "45000",
"annual_revenue" => "0",
"rating" => "Active",
"smcreatorid" => "418176000000047003",
"created_by" => "Amit Patil",
"modifiedby" => "418176000000047003",
"modified_by" => "Amit Patil",
"created_time" => "2012-04-05 19:58:00",
"modified_time" => "2012-05-02 08:51:08",
"street" => "",
"city" => "",
"state" => "",
"zip_code" => "0",
"country" => "",
"description" => "",
"skype_id" => "",
"email_opt_out" => "false",
"salutation" => "Mr.",
"secondary_email" => ""
);
$arr3 = array("lead owner" => "Amit Patil");
$arr4 = array("lead owner" => "Amit aaa");
print_r(array_diff($arr1,$arr2));
echo "<br>";
print_r(array_diff($arr3,$arr4));
?>
输出如下
Array ( [company] => SAM )
Array ( [lead owner] => Amit Patil )
您误会了。
array_diff的文档页面说
返回一个数组,其中包含array1中所有其他数组中不存在的所有条目。
但是Amit Patil
存在于第二个数组中,因此它仅返回一个值为SAM
值,并且仅返回一个值不存在于第二个数组中。
如果要在关联数组之间进行区分,以便键值对(而不只是值)很重要,请使用array_diff_assoc
,而不要使用array_diff
。
array_diff()
返回互补值。 因此,您可以这样做:
array_diff(array_merge($arr1, $arr2), array_intersect($arr1, $arr2));
这样,它将起作用。
发生这种情况是因为“ array_diff”函数返回的值出现在第一个数组中的任何键上,而没有出现在第二个数组中的任何键上。
lead_owner“ Amit Patil”不等于第二个数组lead_owner,但等于第二个数组的created_by和Modify_by键。
为此,您应该使用“ array_diff_assoc”。
试试这个,看看,这应该工作
print_r(array_diff_assoc($arr1,$arr2));
echo "<br>";
print_r(array_diff_assoc($arr3,$arr4));
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