[英]Matlab: Color Coding a 3D Plot
我一直在尝试网上寻找我想要的东西,但是我运气不高,所以我想我只是在这里问。
是否可以用其他颜色精确定位并在图形上显示两个图之间有交点的点?
谢谢你提供的所有帮助。
这是代码:
file1 = fopen('C:\Program Files (x86)\Notepad++\avatar1.txt'); % open text file
file2 = fopen('C:\Program Files (x86)\Notepad++\avatar2.txt'); % open text file
file3 = fopen('C:\Program Files (x86)\Notepad++\avatar3.txt'); % open text file
tline1 = fgetl(file1); % read line by line and remove new line characters
tline2 = fgetl(file2); % read line by line and remove new line characters
tline3 = fgetl(file3); % read line by line and remove new line characters
% declare empty arrays
CX1 = [];
CY1 = [];
CZ1 = [];
CX2 = [];
CY2 = [];
CZ2 = [];
CX3 = [];
CY3 = [];
CZ3 = [];
while ischar(tline1) % true if tline is a character array
temp = cell2mat(textscan(tline1, '<%n,%n,%n>'));
% convert all the cell fields to a matrix
CX1 = vertcat(CX1, temp(1));
CY1 = vertcat(CY1, temp(2));
CZ1 = vertcat(CZ1, temp(3));
tline1 = fgetl(file1);
end
while ischar(tline2) % true if tline is a character array
temp = cell2mat(textscan(tline2, '<%n,%n,%n>'));
% convert all the cell fields to a matrix
CX2 = vertcat(CX2, temp(1));
CY2 = vertcat(CY2, temp(2));
CZ2 = vertcat(CZ2, temp(3));
tline2 = fgetl(file2);
end
while ischar(tline3) % true if tline is a character array
temp = cell2mat(textscan(tline3, '<%n,%n,%n>'));
% convert all the cell fields to a matrix
CX3 = vertcat(CX3, temp(1));
CY3 = vertcat(CY3, temp(2));
CZ3 = vertcat(CZ3, temp(3));
tline3 = fgetl(file3);
end
fclose(file1); % close the file
fclose(file2); % close the file
fclose(file3); % close the file
plot3(CX1, CY1, CZ1) % plot the data and label the axises
plot3(CX2, CY2, CZ2)
plot3(CX3, CY3, CZ3)
xlabel('x')
ylabel('y')
zlabel('z')
grid on
axis square
rotate3d on; % activate interactive mouse rotation
更改颜色很简单,这只是在plot3命令中添加颜色代码的一种情况,例如:
plot3(CX1, CY1, CZ1, 'b'); % blue lines/markers
plot3(CX2, CY2, CZ2, 'r'); % red lines/markers
plot3(CX3, CY3, CZ3, 'g'); % green lines/markers
有关颜色代码的更多详细信息,请参见Matlab Colourspec页面 。
取决于您是想要点的交点(即出现在所有3个数据集中的特定点)还是连接点的线的交点,交点可能会更棘手。
我认为前者应该相当容易(未经测试,并假设CX1
等是垂直向量):
figure; % Open up a new figure
hold on; % This means the everything you plot stays in the figure and is not overwritten
% Plot the original points
plot3(CX1, CY1, CZ1, '-*b'); % blue lines/markers
plot3(CX2, CY2, CZ2, '-*r'); % red lines/markers
plot3(CX3, CY3, CZ3, '-*g'); % green lines/markers
% turn those 1xn vectors into 3xn matrices for each set of points
points1 = [CX1, CY1, CZ1];
points2 = [CX2, CY2, CZ2];
points3 = [CX3, CY3, CZ3];
% Find the intersection of the 3 sets
CX_intersect = intersect( points1, intersect( points2, points3, 'rows'), 'rows');
% Draw a scatter plot of the intersection points. the 'mo' means:
% m: magenta in colour, o: circular markers
scatter3( CX_intersect(:,1),CX_intersect(:,2),CX_intersect(:,3),'mo');
相交的工作方式如下:
假设我们有3个矩阵,每个矩阵包含3d点。 我们称它们为A
, B
和C
为了找到所有三个集合之间的交点,我们首先找到仅在A
和B
中相交的点。 现在,我们有了一组已知的点,分别位于A
和B
,所以现在我们只需要检查这些点是否也位于C
中。 我们通过做另一个交叉路口来做到这一点。
我只是将它们链接在一起成为一行代码,这可能不是很有用,所以我深表歉意。 A
, B
, C
交点的代码如下:
D = intersect(A,B,'rows') % we use rows because each row represents a 3D point
E = intersect(C,D,'rows') % E is the intersection of the 3 sets.
然后,我们可以将D代入E = ...
,得到:
E = intersect( intersect(A,B,'rows'), C, 'rows' );
希望有帮助!
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