[英]File Upload Ajax PHP
我有一段使用Ajax和PHP上传图像的JavaScript。
我正在使用几个html页面的开头部分中的javascript,并想知道是否存在一种方法,可以将这些页面中的值传递给Upload.php文件,而不必为每个网页创建单独的Upload.php文件。
JavaScript部分:
<script type="text/javascript" >
$(function(){
var btnUpload=$('#me');
var mestatus=$('#mestatus');
var files=$('#files');
new AjaxUpload(btnUpload, {
action: '../UploadDoc/Upload.php',
name: 'uploadfile',
我想将值传递给Upload.php文件的一部分:
<?php
/* Set the location to upload the file to */
$uploaddir = '../documents/userdocs/';
/* Set the name and file extension of the file being saved */
$file = $uploaddir ."HtmlPage1_".basename($_FILES['uploadfile']['name']);
$file_name= "HtmlPage1_".$_FILES['uploadfile']['name'];
“ HtmlPage1_”将是我需要传递的信息,因为它是唯一更改的部分。
任何帮助,不胜感激。
非常感谢
用你的JavaScript做
$(function(){
var btnUpload=$('#me');
var mestatus=$('#mestatus');
var files=$('#files');
new AjaxUpload(btnUpload, {
action: '../UploadDoc/Upload.php',
name: 'uploadfile',
params: {
pageKey: 'HtmlPage1_'
}
......ETC-CODE......................
或者您的JavaScript代码可以
$(function(){
var btnUpload=$('#me');
var mestatus=$('#mestatus');
var files=$('#files');
new AjaxUpload(btnUpload, {
action: '../UploadDoc/Upload.php?pageKey=HtmlPage1_',
name: 'uploadfile',
......ETC-CODE......................
在您的PHP中执行:
<?php
/* Set the location to upload the file to */
$uploaddir = '../documents/userdocs/';
/* Set the name and file extension of the file being saved */
$file = $uploaddir .$_REQUEST['pageKey'].basename($_FILES['uploadfile']['name']);
$file_name= $_REQUEST['pageKey'].$_FILES['uploadfile']['name'];
......ETC-CODE......................
然后,将每个页面中的javascript代码修改为“ pageKey”参数。
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