jqGrid不显示行

Question

我正在尝试在jqGrid（4.3.2）中显示行，但是还没有成功。 我的网络服务响应是：

{"d":
{"__type":"JSONResponse:pe",
 "ActionType":null,
 "JSONData":"
            {\"total\":1,
             \"page\":1,
             \"records\":5,
             \"rows\":[
                       {\"invid\":1,\"cell\":[{\"invid\":1,\"amount\":500,\"tax\":65,\"total\":565,\"note\":\"myNote 0\"}]},
                       {\"invid\":2,\"cell\":[{\"invid\":2,\"amount\":510,\"tax\":75,\"total\":585,\"note\":\"myNote 1\"}]},
                       {\"invid\":3,\"cell\":[{\"invid\":3,\"amount\":520,\"tax\":85,\"total\":605,\"note\":\"myNote 2\"}]},
                       {\"invid\":4,\"cell\":[{\"invid\":4,\"amount\":530,\"tax\":95,\"total\":625,\"note\":\"myNote 3\"}]},
                       {\"invid\":5,\"cell\":[{\"invid\":5,\"amount\":540,\"tax\":105,\"total\":645,\"note\":\"myNote 4\"}]}
                      ]
            }",
 "Status":false
}

} <-（假设上面的代码中使用了花括号）

我的网格配置看起来像这样：

<script type="text/javascript">
    $(document).ready(function () {

        gridConfig();

    });

    function gridConfig() {
        var request = JSON.stringify(requestData());
        var jsonResponse;

        $("#list").jqGrid({
            url: '/ScriptServices/JsonService.svc/Process',
            ajaxGridOptions: { contentType: 'application/json; charset=utf-8' },
            datatype: 'json',
            postData: { request: function () { return request; } },
            mtype: 'GET',
            colNames: ['Inv No', 'Amount', 'Tax', 'Total', 'Notes'],
            colModel: [
                    { name: 'invid', index: 'invid', width: 55 },
                    { name: 'amount', index: 'amount', width: 80, align: 'right' },
                    { name: 'tax', index: 'tax', width: 80, align: 'right' },
                    { name: 'total', index: 'total', width: 80, align: 'right' },
                    { name: 'note', index: 'note', width: 150, sortable: false }
                  ],
            pager: $('#pager'),
            rowNum: 10,
            rowList: [10, 20, 30],
            sortname: 'invid',
            sortorder: 'desc',
            viewrecords: true,
            jsonReader: {
                root: "d.JSONData.rows",
                page: "d.JSONData.page",
                total: "d.JSONData.total",
                records: "d.JSONData.records",
                cell: "cell",
                id:0
            },
            caption: 'My first grid'
        });

    };

    function requestData() {
        var request;
        request = {
            ActionType: 'GET_GRID_DATA',
            RequestJSONData: '{ }'
        };
        return request;
    }

</script>

我找不到问题。 是否需要其他格式？ 请帮助..

更新1：

现在，在Oleg建议之后，我的数据以正确的json格式出现，但是由于我的json数据中有__type额外字段，因此无法正确呈现。

修改后的json数据如下：

{
"d":
    {"__type":"JSONResponse:pe",
     "ActionType":"GRID_RESP",
     "JSONData":
                {"__type":"JQGridJSONReader:pe",
                "total":1,
                "page":1,
                "records":5,
                "rows":[
                        {"__type":"InvoiceGrid:pe",
                        "invid":1,
                        "cell":[{"__type":"JqGridCell:pe","invid":1,"amount":500,"tax":65,"total":565,"note":"myNote 0"}]},
                        .... and More Rows
                        ]
                },
     "Status":true
}

} <-（假设上面的代码中使用了花括号）

我已经检查了此链接并实现了默认的构造方法建议，在我的情况下， protected internal是不可能的。

我的服务配置如下所示：

<system.serviceModel>
    <services>
        <service name="JsonService" behaviorConfiguration="JsonServiceAspNetAjaxBehavior">
            <endpoint address="" behaviorConfiguration="JsonServiceEndPointBehavior"
                binding="webHttpBinding" contract="JsonService" />
        </service>
    </services>
    <behaviors>
        <endpointBehaviors>
            <behavior name="JsonServiceEndPointBehavior">
                <enableWebScript/>
              <dataContractSerializer ignoreExtensionDataObject="true" />
            </behavior>
        </endpointBehaviors>
        <serviceBehaviors>
            <behavior name="JsonServiceAspNetAjaxBehavior">
                <serviceMetadata httpGetEnabled="true"/>
                <serviceDebug includeExceptionDetailInFaults="true" />
            </behavior>
        </serviceBehaviors>
    </behaviors>
    <serviceHostingEnvironment aspNetCompatibilityEnabled="true"
        multipleSiteBindingsEnabled="true" />
</system.serviceModel>

如果将<webHttp/>应用于endpointBehaviors ，则会收到“ UriTemplate查询值的变量必须具有可通过'QueryStringConverter'转换的类型”错误。

我的WebService看起来像这样：

[ServiceContract(Namespace = "http://www.abhishek.com/portal/json")]
[AspNetCompatibilityRequirements(RequirementsMode = AspNetCompatibilityRequirementsMode.Allowed)]
public class JsonService
{
    [OperationContract]
    [WebInvoke(Method = "GET", RequestFormat = WebMessageFormat.Json,
        ResponseFormat = WebMessageFormat.Json, BodyStyle = WebMessageBodyStyle.WrappedRequest)]
    [GenerateScriptType(typeof(JsonService), ScriptTypeId = "JsonService1")]
    public PresentationEntities.JSONResponse Process(PresentationEntities.JSONRequest request)
    {
        JSONResponse response;

        try
        {
            if (request == null)
            {
                throw new ArgumentNullException("request", string.Format(ExceptionHelper.ARG_NULL_EXP_MSG, "JSONManager"));
            }
            else
            {
                JQGridTransalator gridtransalator = new JQGridTransalator();
                response = gridtransalator.JQGridToJSONResponse(); // fill response.JSONData with JQGridJSONReader
            }
        }
        catch (Exception)
        {
            throw;
        }

        return response;
    }}

JQGridJSONReader看起来像这样：

[DataContract(Name = "JQGridJSONReader", Namespace = "pe")]
public class JQGridJSONReader
{
    public JQGridJSONReader()
    {

    }

    [DataMember(Name = "total", Order = 1)]
    public int Total { get; set; }

    [DataMember(Name = "page", Order = 2)]
    public int Page { get; set; }

    [DataMember(Name = "records", Order = 3)]
    public int Records { get; set; }

    [DataMember(Name = "rows", Order = 4)]
    public List<InvoiceGrid> Rows { get; set; }
}

任何建议从json数据中删除__type。

更新2：

更新代码，以便我可以更清楚地回答我的问题

[DataContract(Name = "InvoiceGrid", Namespace = "pe")]
public class InvoiceGrid
{
    [DataMember(Name = "cell", Order = 2)]
    public List<JqGridCell> Cell { get; set; }
}

[DataContract(Name = "JqGridCell", Namespace = "pe")]
public class JqGridCell
{
    [DataMember(Name = "invid", Order = 1)]
    public int Invid { get; set; }

    [DataMember(Name = "invdate", Order = 2)]
    public DateTime InvDate { get; set; }

    [DataMember(Name = "amount", Order = 3)]
    public double Amount { get; set; }

    [DataMember(Name = "tax", Order = 4)]
    public double Tax { get; set; }

    [DataMember(Name = "total", Order = 5)]
    public double Total { get; set; }

    [DataMember(Name = "note", Order = 6)]
    public string Note { get; set; }
}

Answer 1

您的错误是您将对象d.JSONData数据从对象序列化为JSON 两次 。 可能您手动使用了一些JSON序列化而不是用法对象，并允许.NET序列化数据本身。

怎么可以看到的数据等d.JSONData.rows无法访问，因为d.JSONData是字符串 ，而不是对象rows属性。

Answer 2

已解决的第一个错误：-如@Oleg所建议，我将JSONData（以字符串格式）转换为json对象。 这是由于发送数据之前使用了JSON序列化。

已纠正第二个错误：

我的单元格类型是这样的： List<GridData>和GridData具有单元格内容（这是复杂类型，即GridData ）。 所以我得到这个

"cell":[{"__type":"JqGridCell:pe","invid":1,"amount":500,"tax":65,"total":565,"n‌​ote":"myNote 0"}]},在此单元格中，第一行具有复杂类型。 想象像"cell":[{ComplexType}]所以我在第一个单元格中得到“ [Object object]”，而其他单元格保持为空。

因此，更正后的单元格类型为List<string>为其添加了网格数据，然后将单元格添加至List<InvoiceGrid> 。

        JQGridJSONReader input = new JQGridJSONReader();
        input.Page = 1;
        input.Total = 1;
        input.Records = 5;

        input.Rows = new List<InvoiceGrid>();


        for (int i = 0; i < 5; i++)
        {
            InvoiceGrid invGrid = new InvoiceGrid();
            invGrid.Cell = new List<string>();
            JqGridCell gridrows = new JqGridCell();
            gridrows.Invid = 1 + i;
            gridrows.Amount = 500.00 + (i * 10);
            gridrows.Tax = 65.00 + (i * 10);
            gridrows.Total = gridrows.Amount + gridrows.Tax;
            gridrows.Note = "myNote " + i.ToString();
            invGrid.Cell.Add(gridrows.Invid.ToString());
            invGrid.Cell.Add(gridrows.InvDate.ToString());
            invGrid.Cell.Add(gridrows.Amount.ToString());
            invGrid.Cell.Add(gridrows.Tax.ToString());
            invGrid.Cell.Add(gridrows.Total.ToString());
            invGrid.Cell.Add(gridrows.Note.ToString());
            input.Rows.Add(invGrid);
        }

我以为该错误是因为__type作为额外的json数据。 但是似乎jqGrid忽略了这一点。

我的json数据现在看起来像这样。 注意：-这次我忽略了invid，但可以将其包括在内。

{"d":
{"__type":"JSONResponse:pe",
 "ActionType":"GRID_RESP",
 "JSONData":
            {"__type":"JQGridJSONReader:pe",
             "total":1,
             "page":1,
             "records":5,
             "rows":[
                    {"__type":"InvoiceGrid:pe",
                    "cell":["1","500","65","565","myNote 0"]},
                    {"__type":"InvoiceGrid:pe",
                    "cell":["2","510","75","585","myNote 1"]},
                    {"__type":"InvoiceGrid:pe",
                    "cell":["3","520","85","605","myNote 2"]},
                    {"__type":"InvoiceGrid:pe",
                    "cell":["4","530","95","625","myNote 3"]},
                    {"__type":"InvoiceGrid:pe",
                    "cell":["5","540","105","645","myNote 4"]}
                    ]
            },
 "Status":true
}}

非常感谢@Oleg。