如何转换ASCII字符串C＃中的位序列

Question

如何转换一串位，例如

0100100001100101011011000110110001101111001000000101011101101111011100100110110001100100

像这样的ASCII字符字符串：“ Hello World”？

Answer 1

您需要将它们分成8个字符的字符串（字节），调用Convert.ToByte(str, 2) ，将它们放入byte[] ，然后调用Encoding.ASCII.GetString() 。

Answer 2

此代码示例应该很清楚：

String bits = "01001001000......0001100100"; // shortened here for demo purposes

byte[] bArr = new byte[bits.Length / 8];
for (int i = 0; i < bits.Length / 8; i++)
{
    String part = bits.Substring(i * 8, 8);
    bArr[i] += Convert.ToByte(part, 2);
}
System.Text.ASCIIEncoding encoding = new System.Text.ASCIIEncoding();
Console.WriteLine(encoding.GetString(bArr));

基本上将字符串分成偶数部分，将生成的字节存储在字节数组中，然后以特定的编码进行解析。

Answer 3

public string GetBytesFromBinaryString(String binary)
{
    var list = new List<Byte>();

    for (int i = 0; i < binary.Length; i += 8)
    {
        String t = binary.Substring(i, 8);

        list.Add(Convert.ToByte(t, 2));
    }

    return Encoding.ASCII.GetString(list.ToArray());
}

测试：

var data = GetBytesFromBinaryString("0100100001100101011011000110110001101111001000000101011101101111011100100110110001100100");

输出：

“你好，世界”

Answer 4

使用这个方法

private byte[] GetAsByteArray(string BinaryString)
{
        return Enumerable.Range(0, BinaryString.Length / 8)
            .Select(i => Convert.ToByte(BinaryString.Substring(i * 8, 8), 2)).ToArray();
}

然后像这样称呼它

string binaryString = "0100100001100101011011000110110001101111001000000101011101101111011100100110110001100100";
string convertedText = System.Text.Encoding.ASCII.GetString(GetAsByteArray(binaryString));