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如何在对象的arrayList中进行迭代并通过前缀匹配获取结果集?

[英]How to iterate within arrayList of object and get the result set by prefix matching?

我有以下课程:

class A {
    String s;
}

以下是class A对象列表的列表:

[{1s, 3f, 46h}, {333s, 67b, 1d, 67m, 67h}, {3a, 3x}, {34n, 22o, 34s},
 {40f, 22x, 4m}... and so on]

我需要的是遍历此列表,获取结果,然后推入另一个输出arrayList中。 现在,结果arrayList中将包含什么:

1. Just skip those elements from the above input arrayList
   which have more than one String with same prefix(only the last character
   is the suffix here which will always be a single character alphabet; not digit).
   For example: from the above input arrayList the first element({1s, 3f, 46h}) 
   won't be skipped and will be pushed into the output arrayList
   as it doesn't have any String with the same prefix; as 1, 3 and 46 are different.
   But 2nd, 3rd and 4th elements will be skipped as they have matches
   (three prefixes with same 67 in 2nd element, two prefixes with same 3 in 3rd element
   and two prefixes with same 34 in 4th element).

   So, for the above input arrayList the output arrayList will be:
   [{1s, 3f, 46h}, {40f, 22x, 4m}]

有人可以建议我如何以一种简单有效的方式完成上述工作。 如果可能,请提供一些示例代码。

谢谢!

考虑以下:

我已经尝试了一种逻辑,如果这对您有用,我会很高兴。

`ArrayList<A> arrList` = [{1s, 3f, 46h}, {333s, 67b,67m, 67h}, {3a, 3x}, {40f, 22x, 4m}... and so on]


 ArrayList<String> newList = new ArrayList<String>();

for ( A a: arrList){

        for(String s : a) {

             int[] temp = a.indexOf(s);

             if (temp > 1){

                break; // will break the immediate loop, NOT the Outer loop

             }

            else{
                     newList.add(s);

              }

      }


}

因此,如果我正在为此编写测试,我会发现我需要做的一件事情就是能够确定前缀。 给定带字符串“ 55p”的A,前缀应为“ 55”。 为此编写一个测试。 前缀方法在哪里? 大概在A类本身。 它看起来应该像这样:

public String prefix() {
    return ...;
}

一旦有了该方法,就可以轻松遍历列表中的所有A,并确定它们中的任何一个是否具有相同的前缀。

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