[英]MYSQL - Select most recent of column type entry
我有一个列表:
s_Id(primary int),sup_type(int),sup_date(datetime),sup_req(int)
目前, sup_type中的值范围为0-5。
如何提取每个sup_type (0-5)的最新条目(通过sup_date )。
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
* s_Id * sup_type * sup_date * sup_req *
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
* 1 * 0 * 2012-06-15 10:13:21 * 4 *
* 2 * 0 * 2012-06-15 11:22:01 * 4 *
* 3 * 1 * 2012-06-15 13:23:32 * 4 *
* 4 * 2 * 2012-06-16 08:04:29 * 4 *
* 5 * 1 * 2012-06-16 16:23:24 * 4 *
* 6 * 1 * 2012-06-17 13:14:05 * 4 *
* 7 * 3 * 2012-06-18 13:37:55 * 4 *
* 8 * 4 * 2012-06-19 13:21:52 * 4 *
* 9 * 4 * 2012-06-20 16:15:19 * 4 *
* 10 * 5 * 2012-06-20 16:17:37 * 4 *
* 11 * 0 * 2012-06-20 16:21:53 * 4 *
* 12 * 1 * 2012-06-20 16:28:13 * 4 *
* 13 * 3 * 2012-06-21 12:23:29 * 4 *
* 14 * 3 * 2012-06-22 07:26:41 * 4 *
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
我想提取
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
* s_Id * sup_type * sup_date * sup_req *
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
* 4 * 2 * 2012-06-16 08:04:29 * 4 *
* 9 * 4 * 2012-06-20 16:15:19 * 4 *
* 10 * 5 * 2012-06-20 16:17:37 * 4 *
* 11 * 0 * 2012-06-20 16:21:53 * 4 *
* 12 * 1 * 2012-06-20 16:28:13 * 4 *
* 14 * 3 * 2012-06-22 07:26:41 * 4 *
* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
谢谢。
SELECT
b.*
FROM
(
SELECT sup_type, MAX(sup_date) AS maxsupdate
FROM tbl
GROUP BY sup_type
) a
INNER JOIN
tbl b ON
a.sup_type = b.sup_type AND
a.maxsupdate = b.sup_date
ORDER BY
b.s_Id
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