[英]Search Method for Hashmap
我需要一个哈希图的搜索方法,我不能完全弄清楚该怎么做。 我也在尝试做一个编辑方法,为此我需要这种方法。 我的hashMap是要存储员工数据。 我有MainApp
,Employee类和EmployeeStore
类。 有人可以帮忙吗?
public class MainApp
{
public static void main(String[] args)
{
new MainApp().start();
}
public void start()
{
EmployeeStore Store = new EmployeeStore();
Store.add(new Employee ("James O' Carroll", 18,"hotmail.com"));
Store.add(new Employee ("Andy Carroll", 1171,"yahoo.com"));
Store.add(new Employee ("Luis Suarez", 7,"gmail.com"));
Store.print();
Store.clear();
Store.print();
Store.add(new Employee ("James O' Carroll", 18,"hotmail.com"));
Store.add(new Employee ("Andy Carroll", 1171,"yahoo.com"));
Store.add(new Employee ("Luis Suarez", 7,"gmail.com"));
Store.print();
Store.remove("Andy Carroll");
Store.print();
}
}
//Imports.
import java.util.HashMap;
//********************************************************************
import java.util.Map;
public class EmployeeStore
{
HashMap<String, Employee> map;
//Constructor.
public EmployeeStore()
{
map = new HashMap<String,Employee>();
}
//********************************************************************
//Hashmap Methods.
//Add to the Hashmap : Employee.
public void add(Employee obj)
{
map.put(obj.getEmployeeName(), obj);
}
//********************************************************************
//Remove from the Hashmap : Employee.
public void remove(String key)
{
//Remove the Employee by name.
map.remove(key);
}
//********************************************************************
//Clear the Hashmap : Employee.
public void clear()
{
map.clear();
}
//********************************************************************
//Print the Hashmap : Employee.
public void print()
{
System.out.println("\n********Employee's in the Company.********");
for (Employee employee : map.values())
{
System.out.println("Employee Name:\t" + employee.getEmployeeName());
System.out.println("Employee Id:\t" + employee.getEmployeeId());
System.out.println("E-mail:\t"+ employee.getEmployeeEmail());
}
}
//********************************************************************
//********************************************************************
}
//Imports:
//********************************************************************
//Employee Class.
public class Employee
{
//Variables.
private String employeeName;
private int employeeId;
private String employeeEmail;
//********************************************************************
//Constructor.
public Employee(String employeeName, int employeeId, String employeeEmail)
{
this.employeeName = employeeName;
this.employeeId = employeeId;
this.employeeEmail = employeeEmail;
}
//********************************************************************
//Getters.
public String getEmployeeEmail() {
return employeeEmail;
}
public void setEmployeeEmail(String employeeEmail) {
this.employeeEmail = employeeEmail;
}
public String getEmployeeName() {
return employeeName;
}
public int getEmployeeId() {
return employeeId;
}
//********************************************************************
//toString method.
public String toString() {
return "Employee [employeeName=" + employeeName + ", employeeId="
+ employeeId + ", employeeEmail=" + employeeEmail + "]";
}
//********************************************************************
}
因为这是家庭作业,所以我只会指导您。
您有两种选择:
首先是创建其他地图,映射id
- Employee
和email
- Employee
,然后在添加新员工时填写所有三张地图。 招募员工将需要在其中一张地图上使用Map.get(key)方法。
其次 ,似乎更适合您的需要, 选项是从map检索所有值-使用Map.values() ,对其进行迭代(使用foreach ),并检查给定员工的id
或email
是否是您要找的那个-使用object.equals(object2)
方法。
最后一件事-尝试编写简洁的代码 ,因此要精确命名-代替:
public void add(Employee obj)
{
map.put(obj.getEmployeeName(), obj);
}
尝试以下:
public void add(Employee employee)
{
map.put(employee.getEmployeeName(), employee);
}
确实有所作为,相信我:)
编辑:
回到命名建议 -当您拥有Named Employee
类时,其内含单词Employee
多余的name方法-就像对employee.getEmployeeName()
。
很明显,您想要获取empoyee的名称,而不是他的狗,也不要沙发:) employee.getName()
(获取名为name的字段的值-不是myName或employeeName )是最简单的,最好的主意是: )
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