[英]Iterator arithmetic
在C ++ STL,如果我有一个迭代it到载体v ,是it - v.begin()保证给我的索引入载体,使得*it == v[it - v.begin()] ? 如果是这样,对于所有随机访问迭代器都是如此吗?
it
v
it - v.begin()
*it == v[it - v.begin()]
是的,它是,并且所有RA迭代器都是如此。
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