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VBA-需要创建一个函数,它将范围作为输入

[英]VBA- Need to create a function, which takes the range as input

我在Excel中有一个二维表。 例如。

outputproduct      blending combination
**5                P1:0.6/P3:0.5**
  2                P1:0.3/P2:0.7
  4                P5:0.4/P2:0.7
  7                P11:0.7/P7:0.4

假设表的范围从B2:C6变化(它可以变化)。 我必须创建一个函数,其第一个工作是读取此范围(这将是用户定义的输入),然后将数据存储到二维数组中,以便我可以使用第一列中的数据(整数)和适当地在第二列中的字符串。

第一列是所得产物指数,而第二列是给定比例的混合产物,它们组合在一起以得到第一栏中的产物。

然后是另一张桌子:

product index      current stock    updated stock
      **1**             **10**
        2                 20 
      **3**             **50**
        4                 15
      **5**             **100**
        .                 .
        .                 .
        .                 .

我必须在数据处理后更新此表中的库存量。 例如,在产物1与产物3以6:5(单位)的比例组合时,产生1单位产物5。 因此,我必须更新表2中每种产品的库存量。

任何建议,如何将范围转换为二维数组?

Public Function Blending_function( R1 as Range, R2 as Range)
 ' R2 is the range of table 2, where the updating is to be done
 ' R1 is first stored in to a 2 dimensional array, such that the data in the
 ' column 1 could be read, and the data in the column 2 could be read (of table 1).
 ' the integer in the column 1 of table 1 refers to the product index in table 2.
 ' P(i) stands for the ith product. In first row of table-1, P1 and P3 combine in the 
 ' ratio of 6:5 to give P5. The current stock of each product is provide in table-2,
 ' whose range is R2(entire table 2).

 ' R1 is the range of table 1, from where the processing is to be done


End Function 

对我来说,主要障碍是将范围R1(表-1)转换为二维数组。 然后从该数组中查看输出产品的索引,并在表2中找到该产品以更新库存水平。

以下是如何使用2D数组的示例。 该函数将分解blending combination并提取所需的值,以便您可以使用它们。

Sub Sample()
    Dim Rng1 As Range, Rng2 As Range

    On Error Resume Next
    Set Rng1 = Application.InputBox("Please select the Table1 Range", Type:=8)
    On Error GoTo 0

    If Rng1.Columns.Count <> 2 Then
        MsgBox "Please select a range which is 2 columns wide"
        Exit Sub
    End If

    On Error Resume Next
    Set Rng2 = Application.InputBox("Please select the Table2 Range", Type:=8)
    On Error GoTo 0

    If Rng2.Columns.Count <> 3 Then
        MsgBox "Please select a range which is 3 columns wide"
        Exit Sub
    End If

    Blending_function Rng1, Rng2

End Sub

Public Function Blending_function(R1 As Range, R2 As Range)
    Dim MyAr1 As Variant, MyAr2 As Variant
    Dim i As Long
    Dim blndCom As String, OutputPrd As String
    Dim ArP1() As String, ArP2() As String, tmpAr() As String

    MyAr1 = R1

    For i = 2 To UBound(MyAr1, 1)
        OutputPrd = MyAr1(i, 1)
        blndCom = MyAr1(i, 2)
        tmpAr = Split(blndCom, "/")

        ArP1 = Split(tmpAr(0), ":")
        ArP2 = Split(tmpAr(1), ":")

        Debug.Print OutputPrd
        Debug.Print Trim(ArP1(0))
        Debug.Print ArP1(1)
        Debug.Print ArP2(0)
        Debug.Print ArP2(1)
        Debug.Print "-------"
    Next
End Function

快照

在此输入图像描述

获得这些值后,您可以使用.FindR2范围内搜索product index ,然后使用.Offset输入公式。

我不确定我是否理解了整个故事,但这是一个回归的功能
多维数组可能如下所示:

Public Sub Main_Sub()

Dim vArray_R1()                     As Variant
Dim oRange                          As Range


Set oRange = ThisWorkbook.Sheets(1).Range("A1:B5")
vArray_R1 = Blending_function(oRange)
'You do the same for The second array.     

set oRange = nothing

End Sub

Public Function Blending_function(R1 As Range)

 Dim iRange_Cols As Integer
 Dim iRange_Rows As Integer


iRange_Cols = R1.Columns.Count
iRange_Rows = R1.Rows.Count

'Set size of the array (an existing array would be cleared)
ReDim vArray(1 To iRange_Rows, 1 To iRange_Cols)

vArray = R1
Blending_function = vArray

End Function

第二个选项可能是声明函数返回一个布尔值,因为参数是标准发送的byRef; 你可以只在main sub中声明范围和数组,并在函数中同时转换它们。 我不会选择此选项,因为您之后无法重新使用该函数将其他范围转换为数组。

补充信息:这种技术有两种方式。 您可以在之后定义范围并执行:

set oRange = vArray

这是在Range与数组大小相同的条件下。

row = 2
column = "B"
Do While Len(Range(column & row).Formula) > 0
    ' repeat until first empty cell in column 'column'(user input)
    ' read (column, row) and (column+1, row) value
     Cells(row, column).Value
     Cells(row, column+1).value
    ' store in Array
Loop

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