PHP的Zend路由变量

Question

Zend_Route代码问题

该代码有效。

resources.router.routes.babynameslist.route               = "baby-names/baby-boy-names-list-from/:char
resources.router.routes.babynameslist.defaults.module     = "default"
resources.router.routes.babynameslist.defaults.controller = "index"
resources.router.routes.babynameslist.defaults.action     = "babynameslist"

http://example.com/baby-names/baby-boy-names-list-from/a/

但是我想用这个。

resources.router.routes.babynameslist.route               = "baby-names/baby-boy-names-list-from-:char/"
resources.router.routes.babynameslist.defaults.module     = "default"
resources.router.routes.babynameslist.defaults.controller = "index"
resources.router.routes.babynameslist.defaults.action     = "babynameslist"

它不起作用（-：char /）

http://example.com/baby-names/baby-boy-names-list-from-a/

请帮助我如何制作“婴儿名字列表”

Answer 1

我认为您应该将“ a”传递给变量，并让您适应脚本。 我不确定，但我认为动态路由在Zend_Route中不起作用。

例如 ：

http://example.com/baby-names/baby-boy-names-list-from/a

Answer 2

您可以考虑使用Zend_Controller_Router_Route_Regex 。
定义如下：

resources.router.routes.babynameslist.type                = "Zend_Controller_Router_Route_Regex"
resources.router.routes.babynameslist.route               = "baby-names/baby-boy-names-list-from-(\w)/"
resources.router.routes.babynameslist.map.1               = "char"
resources.router.routes.babynameslist.defaults.module     = "default"
resources.router.routes.babynameslist.defaults.controller = "index"
resources.router.routes.babynameslist.defaults.action     = "babynameslist"