如何将变量从Android活动提交到网站网址？

Question

我建立了一个应用程序，该应用程序的工作方式类似于表单，它包含四个字段并验证信息以确保没有输入无效字符。 这四个字段存储在变量中：

电话
名称
电子邮件

现在，我想将表单数据（无论输入到这四个字段中并存储到变量中）提交到url（将使用http://www.test.com ），但是我不确定如何执行此操作。 我想我正在寻找一种叫做HttpURLConnection的东西，但是我不确定如何指定发送哪个变量。 我从网站http://developer.android.com/reference/java/net/HttpURLConnection.html找到以下代码

 private class UploadFilesTask extends AsyncTask<URL, Integer, Long>{ protected Long doInBackground(URL... urls) { try { HttpClient http = new DefaultHttpClient(); HttpPost post = new HttpPost("http://www.test.com"); List<NameValuePair> data = new ArrayList<NameValuePair>(); data.add(new BasicNameValuePair("phone", "value")); data.add(new BasicNameValuePair("name", "value")); data.add(new BasicNameValuePair("email", "value")); data.add(new BasicNameValuePair("comments", "value")); post.setEntity(new UrlEncodedFormEntity(data)); HttpResponse response = http.execute(post); // do something with the response } catch (ClientProtocolException e) { // do something finish(); } catch (IOException e) { // do something finish(); }

}

任何帮助将不胜感激，谢谢！

Answer 1

将表单数据发送到服务器的最简单方法是使用HttpClient和HttpPost。

尝试这样的事情：

try {
    HttpClient http = new DefaultHttpClient();
    HttpPost   post = new HttpPost("http://www.example.com/process");

    List<NameValuePair> data = new ArrayList<NameValuePair>();
    data.add(new BasicNameValuePair("phone", "value");
    data.add(new BasicNameValuePair("name", "value");
    data.add(new BasicNameValuePair("email", "value");
    data.add(new BasicNameValuePair("comments", "value");
    post.setEntity(new UrlEncodedFormEntity(data));

    HttpResponse response = http.execute(post);
    // do something with the response
}
catch (ClientProtocolException e) {
    // do something
}
catch (IOException e) {
    // do something
}

请注意，您需要在AsyncTask中执行此操作，因此您不必锁定UI线程即可等待网络操作完成。

编辑

这是一个简单的快速示例，它看起来像在AsyncTask中。

public class SendTask extends AsyncTask<Void, Void, Boolean> {

    String responseString;

    @Override
    protected Boolean doInBackground(Void... params) {
        try {

            HttpClient http = new DefaultHttpClient();
            HttpPost post = new HttpPost("http://www.test.com");

            List<NameValuePair> data = new ArrayList<NameValuePair>();
            data.add(new BasicNameValuePair("phone", "value"));
            data.add(new BasicNameValuePair("name", "value"));
            data.add(new BasicNameValuePair("email", "value"));
            data.add(new BasicNameValuePair("comments", "value"));
            post.setEntity(new UrlEncodedFormEntity(data));

            HttpResponse response = http.execute(post);
            responseString = new BasicResponseHandler().
                                 handleResponse(response); // Basic handler
            return true;
        }
        catch (ClientProtocolException e) {
            // do something useful to recover from the exception
            // Note: there may not be anything useful to do here
        }
        catch (IOException e) {
            // do something useful to recover from the exception
            // Note: there may not be anything useful to do here
        }           
        return false;
    }
    @Override
    protected void onPostExecute(Boolean success) {
        // TODO: Do something more useful here
        if (success) {
            Toast.makeText(MainActivity.this, "Success: " + responseString, Toast.LENGTH_LONG).show();
        } else {
            Toast.makeText(MainActivity.this, "Failed", Toast.LENGTH_LONG).show();
        }
    }
}

Answer 2

将字段添加到url作为参数。

String phone="phone=234432";
String name="name=John Smith";
String email="email=test@email.com"; 

Url = new URL("http://www.test.com?"+phone+"&"+name+"&"+email);

未经测试，但它应在GET Http请求中工作。

Answer 3

//使用xml请求

String url="http://www.test.com";
String xmlRequest="<message xmlns=\"http://test.com/schemas/ma\"><header></header>"+
"<body><phone>9944556622</phone><name>Mytest name</name><email>mytest@email.com</email>"+"<comments>hay this seems nice</comments></body></message>"

HttpPost httppost = new HttpPost(url);
    StringEntity se = new StringEntity(xmlRequest,HTTP.UTF_8);


httppost.setHeader("Content-Type","application/xml");
httppost.setHeader("Accept","application/xml");

httppost.setEntity(se);

BasicHttpResponse httpResponse = (BasicHttpResponse) httpclient.execute(httppost);

   StatusLine statusLine = httpResponse.getStatusLine();

Answer 4

    HttpClient httpClient = new DefaultHttpClient();
                    Log.i("sampath","line 139");
                    HttpPost httpPost = new HttpPost(url);

                    BasicNameValuePair usernameBasicNameValuePair = new BasicNameValuePair("textMessage", msg);

                    List<NameValuePair> nameValuePairList = new ArrayList<NameValuePair>();
                    nameValuePairList.add(usernameBasicNameValuePair);

                    try {

                        UrlEncodedFormEntity urlEncodedFormEntity = new UrlEncodedFormEntity(nameValuePairList);


                        httpPost.setEntity(urlEncodedFormEntity);

                        try {

                            HttpResponse httpResponse = httpClient.execute(httpPost);


                            InputStream inputStream = httpResponse.getEntity().getContent();

                            InputStreamReader inputStreamReader = new InputStreamReader(inputStream);

                            BufferedReader bufferedReader = new BufferedReader(inputStreamReader);

                            StringBuilder stringBuilder = new StringBuilder();

                            String bufferedStrChunk = null;

                            while((bufferedStrChunk = bufferedReader.readLine()) != null){
                                stringBuilder.append(bufferedStrChunk);
                            }

                            return stringBuilder.toString();

                        } catch (ClientProtocolException cpe) {
                            System.out.println("Firstption caz of HttpResponese :" + cpe);
                            cpe.printStackTrace();
                        } catch (IOException ioe) {
                            System.out.println("Secondption caz of HttpResponse :" + ioe);
                            ioe.printStackTrace();
                        }

                    } catch (UnsupportedEncodingException uee) {
                        System.out.println("Anption given because of UrlEncodedFormEntity argument :" + uee);
                        uee.printStackTrace();
                    }

//---------------------------------------------------------------------------
Here is the php file

<?php
$message = $_POST['textMessage'];
echo 'working fine'.$message;
$filename="androidmessages.html";
file_put_contents($filename,"Entered Text is:".$message."<br />",FILE_APPEND);
?>

如何将变量从Android活动提交到网站网址？

问题描述

4 个解决方案

解决方案1
5 已采纳 2012-07-23 14:27:52

解决方案2
1 2012-07-23 14:26:57

解决方案3
0 2012-07-23 15:41:03

解决方案4
0 2015-07-21 15:25:50

如何将变量从Android活动提交到网站网址？

问题描述

4 个解决方案

解决方案1 5 已采纳 2012-07-23 14:27:52

解决方案2 1 2012-07-23 14:26:57

解决方案3 0 2012-07-23 15:41:03

解决方案4 0 2015-07-21 15:25:50

解决方案1
5 已采纳 2012-07-23 14:27:52

解决方案2
1 2012-07-23 14:26:57

解决方案3
0 2012-07-23 15:41:03

解决方案4
0 2015-07-21 15:25:50