Mysql：从表中选择不在另一个表中的行

Question

如何选择一个表中没有出现在另一个表中的所有行？

表格1：

+-----------+----------+------------+
| FirstName | LastName | BirthDate  |
+-----------+----------+------------+
| Tia       | Carrera  | 1975-09-18 |
| Nikki     | Taylor   | 1972-03-04 |
| Yamila    | Diaz     | 1972-03-04 |
+-----------+----------+------------+

表2：

+-----------+----------+------------+
| FirstName | LastName | BirthDate  |
+-----------+----------+------------+
| Tia       | Carrera  | 1975-09-18 |
| Nikki     | Taylor   | 1972-03-04 |
+-----------+----------+------------+

Table1 中不在 Table2 中的行的示例输出：

+-----------+----------+------------+
| FirstName | LastName | BirthDate  |
+-----------+----------+------------+
| Yamila    | Diaz     | 1972-03-04 |
+-----------+----------+------------+

也许这样的事情应该有效：

SELECT * FROM Table1 WHERE * NOT IN (SELECT * FROM Table2)

Answer 1

您需要根据列名进行子选择，而不是* 。

例如，如果您有两个表共有的id字段，则可以执行以下操作：

SELECT * FROM Table1 WHERE id NOT IN (SELECT id FROM Table2)

有关更多示例，请参阅MySQL子查询语法 。

Answer 2

如果您在另一条注释中提到了300列，并且想要在所有列上进行比较（假设列都是相同的名称），则可以使用NATURAL LEFT JOIN隐式连接两个表之间的所有匹配列名这样您就不必繁琐地手动输入所有连接条件：

SELECT            a.*
FROM              tbl_1 a
NATURAL LEFT JOIN tbl_2 b
WHERE             b.FirstName IS NULL

Answer 3

SELECT *
FROM Table1 AS a
WHERE NOT EXISTS (
  SELECT *
  FROM Table2 AS b 
  WHERE a.FirstName=b.FirstName AND a.LastName=b.Last_Name
)

EXISTS将帮助您......

Answer 4

标准LEFT JOIN可以解决问题， 如果连接上的字段被编入索引，
也应该更快

SELECT *
FROM Table1 as t1 LEFT JOIN Table2 as t2 
ON t1.FirstName = t2.FirstName AND t1.LastName=t2.LastName
WHERE t2.BirthDate Is Null

Answer 5

尝试：

SELECT * FROM table1
    LEFT OUTER JOIN table2
    ON table1.FirstName = table2.FirstName and table1.LastName=table2.LastName
    WHERE table2.BirthDate IS NULL

Answer 6

试试这个简单的查询。 它完美地运作。

select * from Table1 where (FirstName,LastName,BirthDate) not in (select * from Table2);

Answer 7

这在Oracle中对我有用：

SELECT a.* 
    FROM tbl1 a 
MINUS 
SELECT b.* 
    FROM tbl2 b;

Answer 8

一个选项是

SELECT A.*
    FROM TableA as A
    LEFT JOIN TableB as B
    ON A.id = B.id
    Where B.id Is NULL

Answer 9

SELECT a.* FROM 
FROM tbl_1 a
MINUS
SELECT b.* FROM 
FROM tbl_2 b